我对访问 pandas 列的各种方式之间的性能差异感到困惑。
In [1]: df = pd.DataFrame([[1,1,1],[2,2,2]],columns=['a','b','c'])
In [2]: %timeit df['a']
The slowest run took 75.37 times longer than the fastest. This could
mean that an intermediate result is being cached.
100000 loops, best of 3: 3.12 µs per loop
In [3]: %timeit df.a
The slowest run took 5.14 times longer than the fastest. This could
mean that an intermediate result is being cached.
100000 loops, best of 3: 6.59 µs per loop
In [4]: %timeit df.loc[:,'a']
10000 loops, best of 3: 55 µs per loop
我知道最后一个变体比较慢,因为它可以设置值,而不仅仅是访问值。但为什么 df.a
比 df['a']
慢?无论缓存的中间结果如何,这似乎都是正确的。
最佳答案
Here是一个链接,解释了 .
访问和 []
访问之间的区别。
另请查看文档中这些运算符的行为
getitem (对于 []
)和 getattr (对于 .
)方法。
.
似乎通过函数调用访问该列,因此比作为字典键值访问的 []
花费的时间更少
关于python - 访问 Pandas 专栏的最快方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45004573/