有一个这样的表:,
name ZK04_COUNT ZK05_COUNT ZK04_PRICE ZK05_PRICE
A 15 0 150.00 0
A 0 20 0 223.00
B 11 0 75.00 0
B 0 24 0 250.00
我正试图将它转向这样的东西:
name ZK04_COUNT ZK05_COUNT ZK04_PRICE ZK05_PRICE
A 15 20 150.00 223.00
B 11 24 75.00 250.00
我的代码是这样的:
SELECT *
FROM (
SELECT
r.name
,r.AUART
, CASE WHEN r.AUART = 'ZK05' THEN count(r.MATNR) ELSE '' END AS ZK05_COUNT
, CASE WHEN r.AUART = 'ZK04' THEN count(r.MATNR) ELSE '' END AS ZK04_COUNT
, CONVERT(money, sum(CAST(netpr as MONEY)), 1) as ToplamTutar
FROM GARANTI_YP_RAPORU as r
group by r.name ,r.AUART
) as gTablo
PIVOT
(
SUM(ToplamTutar)
FOR gTablo.AUART IN ([ZK05],[ZK04])
)
AS p1
我希望单行输出。怎么做到的?
最佳答案
这真的不需要 PIVOT。
仅按名称对它们进行分组,然后使用条件聚合应该可以。
SELECT r.name
, COUNT(CASE WHEN r.AUART = 'ZK04' THEN r.MATNR END) AS ZK04_COUNT
, COUNT(CASE WHEN r.AUART = 'ZK05' THEN r.MATNR END) AS ZK05_COUNT
, CAST(SUM(CASE WHEN r.AUART = 'ZK04' THEN r.netpr ELSE 0 END) AS MONEY) AS ZK04_PRICE
, CAST(SUM(CASE WHEN r.AUART = 'ZK05' THEN r.netpr ELSE 0 END) AS MONEY) AS ZK05_PRICE
FROM GARANTI_YP_RAPORU as r
GROUP BY r.name
ORDER BY r.name
关于sql - 如何使用数据透视表进行分组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57520660/