我是 AWS 的新手,我正在尝试从 Java 程序对本地 DynamoDB 执行 CRUD 操作。 Java 程序是一个 AWS 示例。
我安装了 AWS CLI 并设置了以下配置 - 根据 AWS 文档,我不需要本地 DynamoDB 的真正 AWS 访问和 key 。
我通过在 AWS CLI 中运行 aws configure 在 ~/.aws/config 和 ~/.aws/credentials 中设置了以下值。
[default]
aws_access_key_id = ''
aws_secret_access_key = ''
[default]
region = ap-south-1
我有运行这个的本地 DYnamoDB JAR。
java -Djava.library.path=./DynamoDBLocal_lib -jar DynamoDBLocal.jar -sharedDb
我试图运行的代码是这样的。
https://github.com/aws-samples/aws-dynamodb-examples/blob/master/src/main/java/com/amazonaws/codesamples/datamodeling/ObjectPersistenceCRUDExample.java
然而,我收到了这个异常。
AmazonDynamoDBException: The security token included in the request is invalid.
完整的堆栈是这样的。
Exception in thread "main" com.amazonaws.services.dynamodbv2.model.AmazonDynamoDBException: The security token included in the request is invalid. (Service: AmazonDynamoDBv2; Status Code: 400; Error Code: UnrecognizedClientException; Request ID: UPGRD2BRNUN6S1702EN6N6S8RJVV4KQNSO5AEMVJF66Q9ASUAAJG)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.handleErrorResponse(AmazonHttpClient.java:1695)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.executeOneRequest(AmazonHttpClient.java:1350)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.executeHelper(AmazonHttpClient.java:1101)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.doExecute(AmazonHttpClient.java:758)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.executeWithTimer(AmazonHttpClient.java:732)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.execute(AmazonHttpClient.java:714)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.access$500(AmazonHttpClient.java:674)
at com.amazonaws.http.AmazonHttpClient$RequestExecutionBuilderImpl.execute(AmazonHttpClient.java:656)
at com.amazonaws.http.AmazonHttpClient.execute(AmazonHttpClient.java:520)
at com.amazonaws.services.dynamodbv2.AmazonDynamoDBClient.doInvoke(AmazonDynamoDBClient.java:4192)
at com.amazonaws.services.dynamodbv2.AmazonDynamoDBClient.invoke(AmazonDynamoDBClient.java:4159)
at com.amazonaws.services.dynamodbv2.AmazonDynamoDBClient.executeUpdateItem(AmazonDynamoDBClient.java:3868)
at com.amazonaws.services.dynamodbv2.AmazonDynamoDBClient.updateItem(AmazonDynamoDBClient.java:3835)
at com.amazonaws.services.dynamodbv2.datamodeling.DynamoDBMapper$SaveObjectHandler.doUpdateItem(DynamoDBMapper.java:854)
at com.amazonaws.services.dynamodbv2.datamodeling.DynamoDBMapper$2.executeLowLevelRequest(DynamoDBMapper.java:594)
at com.amazonaws.services.dynamodbv2.datamodeling.DynamoDBMapper$SaveObjectHandler.execute(DynamoDBMapper.java:733)
at com.amazonaws.services.dynamodbv2.datamodeling.DynamoDBMapper.save(DynamoDBMapper.java:623)
at com.amazonaws.services.dynamodbv2.datamodeling.AbstractDynamoDBMapper.save(AbstractDynamoDBMapper.java:123)
at com.stackroute.Main.testCRUDOperations(Main.java:60
at com.stackroute.Main.main(Main.java:17)
任何帮助将不胜感激。提前致谢。
最佳答案
据我所知,引用的代码中没有任何内容指向 DynamoDB 本地实例。看起来它正确地指向了 DynamoDB。
您需要将端点更改为本地版本。看看 this page 。它有一个将端点更改为 localhost:8080 的示例。
关于java - AWS Local DynamoDB 请求中包含的安全 token 无效,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61346821/