php - 使用 Symfony DomCrawler 获取元素的原始 HTML 代码

Question

HTML 结构:

   <div id="product">
     <p>some text</p>
     <p>some text2</p>
   </div>    

我的 PHP 代码:

$client = new Client();
$crawler = $client->request('GET', $url);
echo $crawler->filter('#product')->text();

返回:

some text some text2

但我需要:

<p>some text</p>
<p>some text2</p>

Answer 1

好吧，有一种方法很丑陋——遍历它的节点:

$html = '';

foreach ($crawler as $domElement) {
    $html.= $domElement->ownerDocument->saveHTML();
}

或者，在您的情况下，您应该遍历过滤后的元素:

$html = '';     
$product = $crawler->filter('#produkt');
 
foreach ($product as $domElement) {
    foreach($domElement->childNodes as $node) {
        $html .= $domElement->ownerDocument->saveHTML($node);
    }
}

来自 documentation