Python:将列值的行收集到一行

Question

我的原始数据框如下:

A B C D
2 10 39 109
1 8 40 111
3 9 38 108
2 11 41 107
3 13 40 112
2 12 39 113

我想要的输出是(根据 A 列值合并行):

A B C D A1 B1 C1 D1 A2 B2 C2 D2
2 10 39 109 11 41 107 12 39 113
1 8 40 111 NA NA NA NA NA NA
3 9 38 108 13 40 112 NA NA NA

Answer 1

使用GroupBy.cumcount与 DataFrame.unstack reshape :

g = df.groupby('A').cumcount()
df1 = df.set_index(['A',g]).unstack().sort_index(level=1, axis=1)
df1.columns = [f'{a}{b}' if b != 0 else a for a, b in df1.columns]
df1 = df1.reset_index()
print (df1)
   A     B     C      D    B1    C1     D1    B2    C2     D2
0  1   8.0  40.0  111.0   NaN   NaN    NaN   NaN   NaN    NaN
1  2  10.0  39.0  109.0  11.0  41.0  107.0  12.0  39.0  113.0
2  3   9.0  38.0  108.0  13.0  40.0  112.0   NaN   NaN    NaN

---

df = df.apply(pd.Categorical)
g = df.groupby('A').cumcount()
df1 = df.set_index(['A',g]).unstack().sort_index(level=1, axis=1)

df1 = df1.apply(lambda x: x.cat.add_categories([0])).fillna(0)
df1.columns = [f'{a}{b}' if b != 0 else a for a, b in df1.columns]
df1 = df1.reset_index()
print (df1)

   A   B   C    D  B1  C1   D1  B2  C2   D2
0  1   8  40  111   0   0    0   0   0    0
1  2  10  39  109  11  41  107  12  39  113
2  3   9  38  108  13  40  112   0   0    0