ios - 在 Ios 中排序时间范围

Question

我有一个类似的数组

<__NSArrayI 0xa8434a0>(
{
    From = "10:01AM";
    Title = Discuss;
    To = "12:00AM";
},
{
    From = "12:01AM";
    Title = Discuss;
    To = "02:00AM";
},
{
    From = "5:01AM";
    Title = Available;
    To = "7:00AM";
},
{
    From = "2:01AM";
    Title = Discuss;
    To = "5:00AM";
},
{
    From = "7:01AM";
    Title = Available;
    To = "12:00pM";
}
)

如何使用 From & to 键按时间范围对该数组进行排序？

我试过如下:

但不是很好

sortedDatesArray = [[unsortedDatesArray sortedArrayUsingComparator: ^(id a, id b) {
    NSDate *d1 = [NSDate dateWithString: s1];
    NSDate *d2 = [NSDate dateWithString: s2];
    return [d1 compare: d2];
}];

帮我解决这个问题。

Answer 1

NSArray *toSortArray = nil; /*The array you want to sort*/
NSArray *sortedArray = nil;

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"hh:mma"];

NSSortDescriptor *descriptorTo = [NSSortDescriptor sortDescriptorWithKey:@"To" ascending:YES comparator:^NSComparisonResult(id obj1, id obj2) {
    NSDate *firstDate = [formatter dateFromString:obj1];
    NSDate *secondDate = [formatter dateFromString:obj2];

    return [firstDate compare:secondDate];
}];

NSSortDescriptor *descriptorFrom = [NSSortDescriptor sortDescriptorWithKey:@"From" ascending:YES comparator:^NSComparisonResult(id obj1, id obj2) {
    NSDate *firstDate = [formatter dateFromString:obj1];
    NSDate *secondDate = [formatter dateFromString:obj2];

    return [firstDate compare:secondDate];
}];

sortedArray = [toSortArray sortedArrayUsingDescriptors:@[descriptorFrom, descriptorTo]];

我希望这能回答您的问题。 :)