我对 BigQuery 和 SQL 比较陌生,所以我遇到的部分困难可能是我不知道如何描述我遇到的问题,以便能够搜索到答案,但我看过所以请温柔点。
我想做的是计算满足一组条件的唯一用户 ID 的总数,并将其除以唯一用户 ID 的总数。
例如统计所有购买过的唯一用户:
SELECT count(userId)
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
WHERE event_value > 0 and event_parameters.Name = "SKU"
GROUP BY userId ORDER BY userId)
并统计独立用户总数
SELECT count(userId)
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
GROUP BY userId ORDER BY userId)
我试着把查询写成
SELECT buyers/total
FROM (SELECT COUNT(userId) AS buyers
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
WHERE event_value > 0 and event_parameters.Name = "SKU"
GROUP BY userId ORDER BY userId),
COUNT(userId) as total
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
GROUP BY userId ORDER BY userId))
但它不起作用。我知道我做的事情从根本上是错误的,但我不确定它是什么。如果有任何帮助,我将不胜感激。
最佳答案
您可以像这样计算不同的用户:
SELECT
EXACT_COUNT_DISTINCT(userId) as buyers
FROM (FLATTEN([table1], user_attribute))
WHERE
event_value > 0
AND event_parameters.Name = "SKU"
连接它们的一种方法是添加一个静态标量值并将其用于连接:
SELECT
buyers/total
FROM (
SELECT
EXACT_COUNT_DISTINCT(userId) AS buyers,
1 AS scalar,
FROM (FLATTEN([table1], user_attribute))
WHERE
event_value > 0
AND event_parameters.Name = "SKU") a
JOIN (
SELECT
COUNT(userId) AS total,
1 AS scalar,
FROM (FLATTEN([table1], user_attribute)) ) b
ON
a.scalar=b.scalar
关于sql - 结合两个多个 bigquery SELECT FROM 语句,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30651161/