我必须并行进行一系列 IO 调用,如果成功则合并调用的内容。如果一个失败,其他人将按正常方式处理,但会显示错误消息。
我关于如何实现这一点的思考过程:Array<TE<E, A>> -> TE<E, Array<A>> -> TE<E, MergedA> -> [E, A]
我目前在做什么:
我目前正在对一组 TE 进行排序,但链中的任何故障都会产生一个左值。
pipe(
sequenceT(TE.taskEither)(arrayofTE), //TE<E,A>[] -> TE<E,A[]>
TE.map(mergeFn), //TE<E, A[]> -> TE<E, MergedA>
???
)
我怎样才能阻止短路?
最佳答案
您可以通过T.task
而不是 TE.taskEither
至 sequence
/sequenceT
( docs ):
Action: execute an array of tasks in parallel, collecting all failures and successes
TaskEither: array.sequence(T.task)(taskEithers) - same for sequenceT
sequence
: 并行运行相同类型的任务import { pipeable as P, taskEither as TE, task as T, array as A, either as E } from "fp-ts";
const arrayofTE: TE.TaskEither<string, number>[] = [
TE.right(1),
TE.right(2),
TE.left("Oh shit")
];
const run = P.pipe(
// change to T.task instead of TE.taskEither here
A.array.sequence(T.task)(arrayofTE),
mergeFn
);
run(); // run side effect
// returns Promise<{"errors":["Oh shit"],"results":[1,2]}>
// whatever merged result you want to have; this one collects all errors and all results
declare function mergeFn(te: T.Task<E.Either<string, number>[]>): T.Task<Results>
type Results = { errors: string[]; results: number[] };
sequenceT
: 并行运行不同类型的任务import { apply as AP /* and others above */ } from "fp-ts";
// Here, TaskEither result can be number | boolean (success case), string on error
const arrayofTE = [TE.right(1), TE.right(true), TE.left("Oh shit")] as const;
const run = P.pipe(
AP.sequenceT(T.task)(...arrayofTE), // we use sequenceT here and pass T.task again
mergeFn
);
declare function mergeFn(a: T.Task<E.Either<string, number | boolean>[]>): T.Task<Results>
这里是沙箱 mergeFn
实现:sequence , sequenceT .
关于typescript - 并行运行一组 TaskEithers,但如果 1 个或多个任务失败则继续,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60471399/