python-3.x - 如何断言在 pytest 中调用了猴子补丁？

Question

考虑以下:

class MockResponse:
    status_code = 200

    @staticmethod
    def json():
        return {'key': 'value'}
                                  # where api_session is a fixture
def test_api_session_get(monkeypatch, api_session) -> None:
    def mock_get(*args, **kwargs):
        return MockResponse()

    monkeypatch.setattr(requests.Session, 'get', mock_get)
    response = api_session.get('endpoint/') # My wrapper around requests.Session
    assert response.status_code == 200
    assert response.json() == {'key': 'value'}
    monkeypatch.assert_called_with(
        'endpoint/',
        headers={
            'user-agent': 'blah',
        },
    )

我如何断言 get我正在修补被调用 '/endpoint'和 headers ?当我现在运行测试时，我收到以下失败消息:FAILED test/utility/test_api_session.py::test_api_session_get - AttributeError: 'MonkeyPatch' object has no attribute 'assert_called_with'我在这里做错了什么？感谢所有提前回复的人。

Answer 1

将添加另一个使用monkeypatch 而不是“你不能使用monkeypatch”的响应
由于 python 有闭包，这里是我可怜的人用 Monkeypatch 做这些事情的方式:

patch_called = False

def _fake_delete(keyname):
    nonlocal patch_called
    patch_called = True
    assert ...

monkeypatch.setattr("mymodule._delete", _fake_delete)
res = client.delete(f"/.../{delmeid}"). # this is a flask client
assert res.status_code == 200
assert patch_called

在您的情况下，由于我们正在通过修补 HTTP 服务器方法处理程序做类似的事情，您可以执行以下操作(不是说这很漂亮):

param_called = None

def _fake_delete(param):
    nonlocal param_called
    patch_called = param
    assert ...

monkeypatch.setattr("mymodule._delete", _fake_delete)
res = client.delete(f"/.../{delmeid}")
assert res.status_code == 200
assert param_called == "whatever this should be"