sequelize.js - 如何在 sequelize 查询中使用 LIKE 运算符？

Question

sequelize.query('(..) WHERE LOWER(u.NOMBRE) LIKE "LOWER(:find)%" AND u.ACTIVO = 1 ', {replacements: {find: req.params.usuario, id: req.session.passport.user}, type: sequelize.QueryTypes.SELECT})

Answer 1

如何根据您的问题使用 $like 的示例:

const Sequelize = require('sequelize');
const Op = Sequelize.Op;

const user = User.findAll({ // or User.findOne
    where: {
        activo: 1, // your search condition
        [Op.like]: [
            { nombre: req.params.nombre } // your $like params
        ],
    }
    attributes: ['id', 'nombre'] // results you want returned
})