node.js - 序列化子查询

Question

在这种情况下，我想根据 orderId 找到每个订单的总准备时间，但是当我这样写时，它只显示第一个结果，

 let prepareOrder = await OrderItem.findAll({
          
    where: {
            options: null,
          },
    
          attributes: ["orderId"],
    
          include: [
            {
              model: Item,
              attributes: [
                [
                  sequelize.fn("sum", sequelize.col("prepareTime")),
                  "totalPrepareTime",
                ],
    
              ],
    
            },
          ],
        });

Answer 1

您需要在外部查询上 朗姆酒 SUM() 。当您在内部查询上运行它时，它返回单行，然后执行 JOIN 这就是为什么您只得到一行的原因。

const prepareOrder = await OrderItem.findAll({
  attributes: [
    "orderId",
    // get the summary at the OrderItem for each related Item
    [
      sequelize.fn("sum", sequelize.col("item.prepareTime")),
      "totalPrepareTime",
    ],
  ],
  // include Item but no attributes for performance
  include: {
    model: Item,
    attributes: [],
  },
  where: {
    options: null,
  },
});