sql - 在 where 上的可接缝中使用一列

Question

我在这段代码中有 3 个表，这些表是:

用户 - 包含有关用户的信息
小部件 - 包含有关小部件的信息
user_widgets - 用于前面表之间的 m-n 关系

最后一个表，除了其他 2 个表的 ids 有 2 个额外的字段:读和写

我用来连接到这些表的代码是

 Widget.belongsToMany(User, { through:User_widget, foreignKey: 'widget_id' });
 User.belongsToMany(Widget, { through:User_widget, foreignKey: 'user_id' });

User_widget 有一个别名为“perms”，所以当我打电话

User.findOne ... then(function(user){
   user.getWidgets().then(function(widgets) {

在返回的小部件对象中，我有 perms 对象，其中包含 2 个读写字段，所以一切正常。

我的问题是我需要过滤小部件，以便我只获得我已读取权限的小部件。

我试过

user.getWidgets({
   where : {
      read : false
   }})

但它会产生一个 sql 查询，如

SELECT "widget"."id", "widget"."name", "perms"."widget_id" AS "perms.widget_id", "perms"."user_id" AS "perms.user_id", "perms"."read" AS "perms.read", "perms"."write" AS "perms.write" 
FROM "widgets" AS "widget" 
WHERE "widget"."read" = false 
INNER JOIN "user_widget" AS "perms" ON "widget"."id" = "perms"."widget_id" AND "perms"."user_id" = '5';

我需要这样的查询:

SELECT "widget"."id", "widget"."name", "perms"."widget_id" AS "perms.widget_id", "perms"."user_id" AS "perms.user_id", "perms"."read" AS "perms.read", "perms"."write" AS "perms.write" 
FROM "widgets" AS "widget" 
INNER JOIN "user_widget" AS "perms" ON "widget"."id" = "perms"."widget_id" AND "perms"."user_id" = '5' AND "perms"."read" = false;

Answer 1

尝试:

user.getWidgets({
  through: {
    where : {
      read : false
    }
  }
})