我有以下实体:
Product [id, name]
Properties [id, name, product_id]
Values [id, name, property_id]
Offer [id, product_id]
OfferDetail [offer_id, property_id, value_id]
我想在 sequelize 中执行以下过滤器:
product_id
[property_1, value_1], [property_2, value_2], ...
这将返回具有相应值的所有产品。
例子:
Products
[{1, Potato}, {2, Tomato}]
Properties
[{1, Color, 1}, {2, Size, 1}, {3, Size, 2}]
Values
[{1, White, 1}, {2, Red, 1}, {3, Small, 2}, {4, Big, 2}, {5, Medium, 2}, {6, Small, 3}, {7, Big, 3}]
Offer
[{1, 1}, {2, 1}, {3, 2}] (I have 3 offers, 2 for potato and 1 for tomato)
OfferDetail
[{1, 1, 1}, {1, 2, 3}, {2, 1, 2}, {3, 3, 6}]
meaning:
Potato: {Color White}, {Size Small}
Potato: {Color Red}
Tomato: {Size Small}
I want to be able to filter:
Potato Small
Potato (White or Red)
or a mix of them.
谢谢
最佳答案
对于这种类型的复杂查询，您可以尝试使用原始查询
select p.name, group_concat(distinct pr.name separator ',') as prNames, group_concat(distinct v.name separator ',') as prValues from OfferDetail od join Offer o on o.id=od.offer_id left join Properties pr on pr.id=od.property_id left join Values v on v.id=od.value_id left join Products p on p.id=o.product_id group by od.offer_id
你能检查一下这个查询吗？
关于node.js - 复杂的过滤器 Sequelize js，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40953180/