node.js - 如何在 sequelize 查询中编写这个 Where 子句？

Question

我有一个 SQL Server SELECT 查询，我想将它转换为 Sequelize 查询生成器:

SELECT ...
FROM usertbl as user
WHERE
[user].[is_deleted] = 0
        AND [user].[id_role] = 6
        AND ( LOWER([user].[cardid_print]) LIKE CONCAT('%', query_string, '%')
              OR LOWER([user].code) LIKE CONCAT('%', query_string, '%')
              OR LOWER([user].[firstname]) LIKE CONCAT('%', query_string, '%')
              OR LOWER([user].lastname) LIKE CONCAT('%', query_string, '%')
              OR LOWER([user].fullnameEN) LIKE CONCAT('%', query_string, '%')
              OR LOWER([user].firstname) LIKE CONCAT('%', query_string, '%')
              OR LOWER([user].idnumber) LIKE CONCAT('%', query_string, '%')
              OR CONCAT(LOWER([user].lastname), ' ', LOWER([user].firstname)) LIKE CONCAT('%', query_string, '%')
            )

如何将其转换为 sequelize 查询选项对象，如下所示:

{
  where: { 
    is_deleted: 0,
    ...
  } 
}

或者像这样:

{
   where: sequelize.where(sequelize.fn('FUNCTION',
            sequelize.col('field')), 'value')
}

编辑1:

查询字符串可以为空，如果查询字符串为空或空字符串，则去掉 where 条件

编辑2:

id_role 可以为空，如 query_string

编辑3:

我发现这种方式没有调用 LOWER/UPPER 函数 here

我已经测试了这段代码，它已经完成了!

感谢您的回答@ChuongTran

Answer 1

你可以试试吗？并让我知道:)

var sequelize = require('sequelize');
        var query_string = 'something..';
        var id_role = 6;
        var query = {
            is_deleted: 0
        }
        if(id_role !== undefined){
            query['id_role'] = id_role;
        }
        if(query_string !== undefined || query_string.length <= 0){
            query['$or'] = sequelize.literal(`( LOWER(cardid_print) LIKE CONCAT('%', ${query_string}, '%')
            OR LOWER(code) LIKE CONCAT('%', ${query_string}, '%')
            OR LOWER(firstname) LIKE CONCAT('%', ${query_string}, '%')
            OR LOWER(lastname) LIKE CONCAT('%', ${query_string}, '%')
            OR LOWER(fullnameEN) LIKE CONCAT('%', ${query_string}, '%')
            OR LOWER(firstname) LIKE CONCAT('%', ${query_string}, '%')
            OR LOWER(idnumber) LIKE CONCAT('%', ${query_string}, '%')
            OR CONCAT(LOWER(lastname), ' ', LOWER(firstname)) LIKE CONCAT('%', ${query_string}, '%')
          )`);
        }
        User.findAll({
            where: query
        })
        .then(users => {

        })
        .catch(err => {
            console.log('err', err);
        });