我有以下查询:
select coalesce(round(sum(vdamesatual) /
(select count(*)
from feriados
where month(data)=month(current_date) and
day(data)<day(current_date) and
diadasemana in(2,3,4,5,6) and
feriadonacional=0 and
uf <> (select distinct uforigem from baseprodutos where Empresa = 'test'))
*
(select count(*)
from feriados
where month(data)=month(current_date) and
day(data)>=day(current_date) and
diadasemana in(2,3,4,5,6) and
feriadonacional=0 and
uf <> (select distinct uforigem from baseprodutos where Empresa = 'test'))),0) as projecao
from baseprodutos
where Empresa = 'test' and
UFDest = 'uf' and
Fabricante = 'sample';
如您所见,我在第一次选择后立即进行了合并,但我无法找到使用 sequelize 编写此内容的正确方法;你有什么建议吗?
最佳答案
我并没有真正遵循您的查询逻辑,但是 Sequelize 中的规则是您可以使用 sequelize.fn()
调用任何函数,因此在 Sequelize 中使用 COALESCE 从具有别名的 2 列中获取值的简单示例如下所示你的 attributes
:
[[sequelize.fn('COALESCE', mysql.col('col_name'), mysql.col('col_2_name')), 'alias'], 'another_col']
如果需要,您可以通过执行以下操作包含另一个函数,例如 SUM
: [[sequelize.fn('COALESCE', sequelize.fn('SUM', (mysql.col('col_name'), mysql.col('col_2_name'))), (some other code here ...)),'alias']]
关于mysql - 在 node.js 上使用 coalesce 和 sequelize,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62975816/