node.js - 如何在 Sequelize 中使用模型名称而不是模型本身进行急切加载

Question

我有以下代码:

const service = await Service.findByPk(req.params.service_id, {
  include: [
    {
      model: User,
      attributes: {
        exclude: ['password'],
      },
    },
  ],
});   

有什么方法可以让我用模型的名称替换模型 User ，这样我就不必导入 User 模型了吗？

Answer 1

选项 1. 您可以使用 sequelize.models 属性。

Models are stored here under the name given to sequelize.define

但是您仍然需要导入 Sequelize 类的实例。

import { Service } from './models';
import { sequelize } from '../../db';

async function controller(req, res) {
  const service = await Service.findByPk(req.params.service_id, {
    include: [
      {
        model: sequelize.models['User'],
        attributes: {
          exclude: ['password'],
        },
      },
    ],
  });
}

db.js :

import { Sequelize } from 'sequelize';

const sequelize = new Sequelize({
  dialect: 'postgres',
  //...
})

export { sequelize }

选项 2. 您可以使用 Model.sequelize 。

A reference to the sequelize instance

这样就不需要导入 Sequelize 类的实例了。您可以从 Model.sequelize 属性获取实例。

import { Service } from './models';

async function controller(req, res) {
  const service = await Service.findByPk(req.params.service_id, {
    include: [
      {
        model: Service.sequelize.models['User'],
        attributes: {
          exclude: ['password'],
        },
      },
    ],
  });
}