mysql - Sequelize 3 个表与 2 个连接表之间的位置

Question

我想在 Sequelize 中复制这个 MySQL 查询:

select u.email, a.serverId, ak.apikey from users u
join accounts a on u.id = a.userId
join apikeys ak on ak.userId = u.id
where u.state = "active" and ak.state = 1 and a.serverId = ak.serverId

这是我的翻译，除了我不知道如何实现的最终 and 子句 ( a.serverId = ak.serverId ):

const activeKeys = await models.User.findAll({
        attributes: ['email'],
        raw: true,
        where: {
            state: "active"
        },
        include: [{
            model: models.Account,
            attributes: ['serverId']
        },
        {
            model: models.Apikey,
            attributes: ['apikey'],
            where: {
                state: 1
            }
        }]
    })

我尝试了多种关联组合，这些是当前的组合:

db.Account.belongsTo(db.User) // account has 1 user
db.User.hasMany(db.Account) // user has multiple accounts
db.User.hasMany(db.Apikey) // user has multiple apikeys
db.Apikey.belongsTo(db.User) // apikey has 1 user
db.Apikey.hasMany(db.Account) // apikey has many accounts
db.Account.hasOne(db.Apikey) // account has 1 apikey

唯一缺少的部分是 2 个包含模型之间的 and 子句。我怎样才能实现它？

Answer 1

在主 where 中尝试这样的事情:

where: Sequelize.and(
  Sequelize.where(Sequelize.col("state"), "=", "active"),
  Sequilize.where(Sequelize.col("Account.serverId"),"=", Sequelize.col("Apikey.serverId"))
)