我开始使用 RXAndroid,并且我已经发布了我的第一个测试版,但我遇到了一个我没想到的异常。我确定这是因为我对 onError
的方式缺乏了解。方法有效。
我的代码是这样的:
disposables.add(Observable.create(new ObservableOnSubscribe<String>() {
@Override
public void subscribe(@NonNull ObservableEmitter<String> e) throws Exception {
if (e.isDisposed()) {
return;
}
//do stuff
if (stuff didn't fail) {
e.onNext(myString);
} else {
e.onError(new Exception("stuff failed"));
}
e.onComplete();
}
})
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribeWith(new DisposableObserver<String>() {
@Override
public void onNext(@NonNull String myString) {
//do stuff
}
@Override
public void onError(@NonNull Throwable e) {
//handle the error
}
@Override
public void onComplete() {
}
})
);
我在这里遇到了崩溃:
e.onError(new Exception("stuff failed"));
但我个人认为这会处理这种情况吗?
public void onError(@NonNull Throwable e) {
//handle the error
}
我已经更改了我的代码以不同的方式处理这个问题,但我仍然想知道如何
onError
应该工作。谢谢你。
编辑:异常(exception):
java.lang.Exception: stuff failed
at io.reactivex.plugins.RxJavaPlugins.onError(RxJavaPlugins.java:349)
at io.reactivex.internal.operators.observable.ObservableCreate$CreateEmitter.onError(ObservableCreate.java:83)
at MyClass$4.subscribe(MyClass.java:295)
at io.reactivex.internal.operators.observable.ObservableCreate.subscribeActual(ObservableCreate.java:40)
at io.reactivex.Observable.subscribe(Observable.java:10842)
at io.reactivex.internal.operators.observable.ObservableSubscribeOn$SubscribeTask.run(ObservableSubscribeOn.java:96)
at io.reactivex.Scheduler$DisposeTask.run(Scheduler.java:452)
at io.reactivex.internal.schedulers.ScheduledRunnable.run(ScheduledRunnable.java:61)
at io.reactivex.internal.schedulers.ScheduledRunnable.call(ScheduledRunnable.java:52)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:272)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
at java.lang.Thread.run(Thread.java:762)
Caused by java.lang.Exception: stuff failed
at MyClass$4.subscribe(MyClass.java:295)
at io.reactivex.internal.operators.observable.ObservableCreate.subscribeActual(ObservableCreate.java:40)
at io.reactivex.Observable.subscribe(Observable.java:10842)
at io.reactivex.internal.operators.observable.ObservableSubscribeOn$SubscribeTask.run(ObservableSubscribeOn.java:96)
at io.reactivex.Scheduler$DisposeTask.run(Scheduler.java:452)
at io.reactivex.internal.schedulers.ScheduledRunnable.run(ScheduledRunnable.java:61)
at io.reactivex.internal.schedulers.ScheduledRunnable.call(ScheduledRunnable.java:52)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:272)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
at java.lang.Thread.run(Thread.java:762)
最佳答案
检查之间 e.isDisposed()
和您调用 e.onError()
发射器最终以某种方式被处置。这会导致调用 onError
回退到全局错误处理程序。
您需要查看e.isDisposed()
再次,或者如果您愿意使用实验性功能,RxJava 2.1.1 添加了 e.tryOnError
如果它已经被处理,则不会回退的方法。
关于rx-java - 通过 RxJava 发送异常时崩溃,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44420422/