javascript - 使用 id 时如何使用 Sequelize 创建关联？

Question

我有一个 warmup 和一个 warmup_step 。我正在尝试创建一个 warmup with an association
但是，当我尝试创建时，它不会将 warmup_id 映射到 warmup_step 。我究竟做错了什么？

// Warmup

module.exports = (sequelize, DATATYPES) => {
  const Warmup = sequelize.define(
    "warmup",
    {
      duration: { type: DATATYPES.INTEGER, allowNull: false },
      name: { type: DATATYPES.STRING, allowNull: false },
    },
    { underscored: true }
  );

  // Assign an associate function on the model
  Warmup.associate = function (models) {
    models.Warmup.hasMany(models.WarmupStep);
  };

  return Warmup;
};

// Warmup Step

module.exports = (sequelize, DATATYPES) => {
  const WarmupStep = sequelize.define(
    "warmup_step",
    {
      duration: { type: DATATYPES.INTEGER, allowNull: false }, // seconds
      exercise_id: { type: DATATYPES.INTEGER, allowNull: false },
      warmup_id: { type: DATATYPES.INTEGER, allowNull: false }, // Map to parent Warmup.
      step_index: { type: DATATYPES.INTEGER, allowNull: false }, // position in warmup.
    },
    { underscored: true }
  );

  // Assign an associate function on the model
  WarmupStep.associate = function (models) {
    models.WarmupStep.belongsTo(models.Warmup, { foreignKey: "warmup_id" });
  };

  return WarmupStep;
};

创建函数:

  Warmup.create(
    {
      name,
      duration,
      warmup_steps,
    },
    {
      include: [WarmupStep],
    }
  )
    .then((data) => res.send(data))
    .catch((err) => {
      console.log("here");
      console.log(err);
    });

我希望创建 warmup ，然后将 id 用于 warmup_steps ，但它给了我错误 message: 'warmup_step.warmup_id cannot be null' 。我认为这就是使用关联创建为您所做的事情？或者我必须在两个电话中做到这一点？

Answer 1

您还应该在 hasMany 关联中指明 warmup_id :

models.Warmup.hasMany(models.WarmupStep, { foreignKey: "warmup_id" });