sequelize.js - 这是在 Sequelize 中定义表关系的正确方法吗？

Question

我发现 Sequelize docs 很长而且很难理解，如果你使用的表不遵循他们的约定。

如果我有两个表:

people
(
  people_id - uuid
  name - text
)

parties
(
  parties_id - uuid 
  people_id - uuid  (foreign key)
)

我这样定义我的模型是否正确？

function getPeople()
{
  let entity = {};
  entity['people_id'] = {type: Sequelize.UUID, primaryKey: true, allowNull : false};
  entity['name'] = Sequelize.TEXT;
  return sequelize.define('dbo.people', entity, options);
}

function getParties()
{
  let entity = {};
  entity['parties_id'] = {type: Sequelize.UUID, primaryKey: true, allowNull : false};
  entity['people_id'] = 
  {
    type: Sequelize.UUID,
    references: {model: getPeople(), key: 'people_id', deferrable: Sequelize.Deferrable.INITIALLY_DEFERRED}
  };      
  const parties = sequelize.define('dbo.parties', entity, options);
  parties.belongsTo(this.getPeople(), {foreignKey: 'people_id'});
  return parties;
}

假设:

如果我省略了“belongsTo”部分，那么据我所知，它实际上并不是一个关联，因此我无法使用 include:[]

在查询中提取相关数据

如果我省略了“references”部分，那么我就无法指定本地字段名称“people_id”与约定“peopleId”不同，也无法设置“deferrable”

我假设我可以使用 getPeople() 返回一个用于外键的类，并且它不必是单例

Answer 1

If I leave out the 'belongsTo' part then as I understand the docs it won't actually be an association, so I couldn't pull out related data in queries using include:[]

正确 - 并且只有belongsTo，您将只能执行Parties.findAll(include People) - 要以相反的方式执行此操作，您还需要设置反向关联。

If I leave out the 'references' part then I have no way of specifying the local field name, 'people_id', to be different from the convention 'peopleId' nor a way of setting 'deferrable'

是的

I assume I can use getPeople() to return a class for use in foreign keys and it doesn't have to be a singleton

如果您有同一个模型的多个实例，您可能会遇到微妙的问题 - 一般模式是在单独的文件中定义每个模型并要求它一次。在需要访问模型的任何地方，您都可以从 sequelize 实例访问它 - 请参阅 https://github.com/sequelize/express-example