sequelize.js - 无法删除 Sequelize 查询中的模型属性

Question

使用 sequelize，我们无法执行包含来自其他模型(播放器)的字段而不包含模型名称作为属性的查询。

我们想获得这个结果(查看每个对象的最后一个属性:数字):

[ { id: '35',
   username: '4f224bd78d1a943ead9db2f73991e93dc8227335',
   firstName: '8c81f070b9adad3d3693',
   lastName: 'f9f5792d8a827e83974b',
   email: 'd6fd38bb112da3a55b23@3c1f780dea427bc097ab.com',
   created_at: '2017-03-16T07:35:15.676Z',
   updated_at: '2017-03-16T07:35:15.676Z',
   deleted_at: null,
   number: null },

 { id: '36',
   username: '613400c032540519fce322f4aa6abdb082834005',
   firstName: '8bbc5692042ea4ce06f6',
   lastName: 'b26d6701c275e07e1ea1',
   email: '59e8d5b35185810a31e5@41677c1723806c2afac0.com',
   created_at: '2017-03-16T07:35:15.768Z',
   updated_at: '2017-03-16T07:35:15.768Z',
   deleted_at: null,
   number: 10 } ]

相反，我们得到了这个:

[ { id: '35',
   username: '4f224bd78d1a943ead9db2f73991e93dc8227335',
   firstName: '8c81f070b9adad3d3693',
   lastName: 'f9f5792d8a827e83974b',
   email: 'd6fd38bb112da3a55b23@3c1f780dea427bc097ab.com',
   created_at: '2017-03-16T07:35:15.676Z',
   updated_at: '2017-03-16T07:35:15.676Z',
   deleted_at: null,
   Player: { number: null } },
 { id: '36',
   username: '613400c032540519fce322f4aa6abdb082834005',
   firstName: '8bbc5692042ea4ce06f6',
   lastName: 'b26d6701c275e07e1ea1',
   email: '59e8d5b35185810a31e5@41677c1723806c2afac0.com',
   created_at: '2017-03-16T07:35:15.768Z',
   updated_at: '2017-03-16T07:35:15.768Z',
   deleted_at: null,
   Player: { number: 10 } } ]

我们涉及到 4 个模型:User(拥有几乎所有的属性)、Player(拥有数字)、Role(包含角色)和 UserRole(关联用户和角色)。

async function getPlayers() {
   const playerRole = await sequelize.models.Role.getPlayerRole();    

   return sequelize.models.User.findAll({
     include: [{
       association: sequelize.models.User.hasOne(sequelize.models.UserRole),
       model: sequelize.models.UserRole,
       where: {
         club_id: this.clubId,
         team_id: this.id,
         role_id: playerRole.id
       }
     }, {
       association: sequelize.models.User.hasOne(sequelize.models.Player),
       model: sequelize.models.Player,
       where: {
         team_id: this.id,
       },
       attributes: ['number']
     }]
   });
 }

Answer 1

您可以使用 sequelize.col() ，但您可能应该将 raw: true 添加到 findAll 调用中，否则结果将被转换为 User 模型实例，因此无论如何都会忽略 number 属性。

return sequelize.models.User.findAll({
    attributes: { include: sequelize.col('Player.number') },
    raw: true, // added to prevent returning User instances from the query, only simple JSON data
    include: [
        {
            model: sequelize.models.UserRole,
            where: {
                club_id: this.clubId,
                team_id: this.id,
               role_id: playerRole.id
            }
        },
        {
            model: sequelize.models.Player,
            where: {
                team_id: this.id,
            },
            attributes: []
        }
    ]
});

我已经删除了 association 属性 - 我假设您已经在模型定义中声明了它们，因此在进行查询时不需要每次都使用它们。

必须在 Sequelize 实例上调用 col() 方法。