javascript - Sequelize错误: column reference "id" is ambiguous.无法在文档中找到答案

Question

我使用 Sequelize 将数据库链接到我的应用程序。但我最近遇到了上面的bug。到处都说这是数据库错误。由于两个表具有相同的主键。在 SQL 中，这是通过别名来解决的。但在 Sequelize 的文档中我还没有找到这个问题的解决方案。我该怎么办？

    const { DataTypes } = require("sequelize");
const db = require("../config/database");

const Office = db.define(
    "Office",
    {
        id: {
            type: DataTypes.INTEGER,
            allowNull: false,
            primaryKey: true,
            autoIncrement: true,
        },
        address: DataTypes.STRING(45),
    },
    {
        // Other model options go here
        tableName: "office",
        timestamps: false,
    }
);

const Employees = db.define(
    "Employees",
    {
        id: {
            type: DataTypes.INTEGER,
            allowNull: false,
            primaryKey: true,
            autoIncrement: true,
        },
        name: DataTypes.STRING(45),
        job: DataTypes.STRING(45),
        reg_date: DataTypes.DATEONLY,
        salary: DataTypes.DECIMAL(10, 2),
        weekend: DataTypes.INTEGER,
        office_id: { type: DataTypes.INTEGER, allowNull: false },
    },
    {
        // Other model options go here
        tableName: "employees",
        timestamps: false,
    }
);

Employees.belongsTo(Office, { foreignKey: "office_id" }); // Foreign key

const Developer = db.define(
    "Developer",
    {
        id: {
            type: DataTypes.INTEGER,
            allowNull: false,
            primaryKey: true,
            autoIncrement: true,
        },
        role: DataTypes.STRING(45),
        level: DataTypes.STRING(45),
        project_count: DataTypes.INTEGER,
    },
    {
        // Other model options go here
        tableName: "developer",
        timestamps: false,
    }
);

// Developer.belongsTo(Employees);
Employees.hasOne(Developer, { foreignKey: "id", targetKey: "id" }); // Foreign key

const Clients = db.define(
    "Clients",
    {
        id: {
            type: DataTypes.INTEGER,
            allowNull: false,
            primaryKey: true,
            autoIncrement: true,
        },
        name: DataTypes.STRING(45),
        total_sum: DataTypes.DECIMAL(20, 2),
    },
    {
        // Other model options go here
        tableName: "clients",
        timestamps: false,
    }
);

const Projects = db.define(
    "Projects",
    {
        id: {
            type: DataTypes.INTEGER,
            allowNull: false,
            primaryKey: true,
            autoIncrement: true,
        },
        price: DataTypes.DECIMAL(15, 2),
        started: DataTypes.DATEONLY,
        ended: DataTypes.DATEONLY,
        teamlead_id: { type: DataTypes.INTEGER, allowNull: false },
        designer_id: { type: DataTypes.INTEGER, allowNull: false },
        programmer_id: { type: DataTypes.INTEGER, allowNull: false },
        dbarch_id: { type: DataTypes.INTEGER, allowNull: false },
        client_id: { type: DataTypes.INTEGER, allowNull: false },
    },
    {
        // Other model options go here
        tableName: "projects",
        timestamps: false,
    }
);

Developer.hasOne(Projects, { foreignKey: "teamlead_id" }); // Foreign key
Developer.hasOne(Projects, { foreignKey: "designer_id" }); // Foreign key
Developer.hasOne(Projects, { foreignKey: "programmer_id" }); // Foreign key
Developer.hasOne(Projects, { foreignKey: "dbarch_id" }); // Foreign key
Clients.hasOne(Projects, { foreignKey: "client_id" }); // Foreign key

module.exports = { Clients, Developer, Employees, Office, Projects };

并明确要求:

app.get("/office_dev_workers_spec_count", (req, res) => {
    Employees.findAll({
        include: {
            model: Developer,
            where: {
                "$Developer.role$": req.query.dev,
                "$Developer.level$": req.query.lvl,
                "$Employees.office_id$": req.query.office,
            },
            attributes: [
                [sequelize.fn("COUNT", sequelize.col("id")), "n_devEmployees"],
            ],
        },
    }).then((result) => {
        res.send(result);
    });
});

Answer 1

两个表都包含字段 id，因此在 COUNT 函数中 SQL 不知道要使用哪个 id。尝试在 sequelize.col("id") 中指定 ID。例如sequelize.col("Employees.id")。