sequelize.js - Sequelize : applying a where clause to a subquery

Question

我试图向子查询添加一个 where 子句，但出现以下错误。我试图做的事情是不可能的吗？

Error: Support for literal replacements in the `where` object has been removed.

models.Message.findAll({
    attributes:  ['createdAt', 'content',
      [
        sequelize.literal(`
            RANK() OVER (
              PARTITION BY DATE_FORMAT('createdAt', '%Y-%m-%d') 
              ORDER BY createdAt DESC
        )`),
        'ranked',
      ]],
      where: [sequelize.literal('ranked') <= 3]
  })

作为引用，这是我尝试在sequelize 中复制的工作MySql 查询。

SELECT * FROM (
    SELECT 
        createdAt,
        content,
        RANK() OVER (
            PARTITION BY DATE_FORMAT(`createdAt`, '%Y-%m-%d') 
            ORDER BY createdAt DESC
            ) AS ranked 
    FROM
        communication_hub.Messages
    ORDER BY createdAt DESC
    ) AS messages
    WHERE ranked <= 3;

Answer 1

我想你应该使用 sequelize.where 将 sequelize.literal 与某些条件结合起来:

where: sequelize.where(sequelize.literal('ranked'), '<=',  3)