node.js - 为什么 sequelize 事务 t.lock.UPDATE 不会阻塞其他事务？

Question

            var promises = [];
            promises.push(
                sequelize.transaction(function(t1) {
                    return models.car_service.findAll({
                        where: sequelize.and(
                            { "id_dtc": 6},
                            { "id_car": 95 }
                        ),
                        transaction: t1,
                        lock: t1.LOCK.UPDATE,
                        logging: console.log
                    }).then(function(result) {
                        console.log(result.dataValues);
                        if(!result.dataValues){
                        return models.car_service.create(
                            {
                                id_dtc: 6,
                                id_car: 95,
                                priority: config.get('apiConfig.coreControllerConfig.createIssueOptions.DTCPriority'),
                                status: 'new',
                                dtc_is_pending: false
                            });
                        }
                    })
                })
            );
            promises.push(
                sequelize.transaction(function(t2) {
                    return models.car_service.findAll({
                        where: sequelize.and(
                            { "id_dtc": 6},
                            { "id_car": 95 }
                        ),
                        transaction: t2,
                        lock: t2.LOCK.UPDATE,
                        logging: console.log
                    }).then(function(result) {
                        console.log(result.dataValues);
                        if(! result.dataValues){
                        return models.car_service.create(
                            {
                                id_dtc: 6,
                                id_car: 95,
                                priority: config.get('apiConfig.coreControllerConfig.createIssueOptions.DTCPriority'),
                                status: 'new',
                                dtc_is_pending: false
                            });
                        }
                    })
                })
            );
            return promise.all(promises).then(function(results) {
                console.log(results);
            });

日志是

Executing (14a1c614-c2f1-46a1-a99f-89bc92ca23dc): SELECT "id", "status",        "priority", "mileage", "done_at", "created_at", "updated_at", "id_car",   "id_service_type", "id_service_edmunds", "id_service_customized", "id_recall_recallmasters", "id_service_archive", "id_service_mmy", "id_service_preset", "id_dtc", "dtc_is_pending" FROM "car_service" AS "car_service" WHERE ("car_service"."id_dtc" = 6 AND "car_service"."id_car" = 95) FOR UPDATE;
Executing (084558cc-730d-441a-a794-aaa27898db77): SELECT "id", "status", "priority", "mileage", "done_at", "created_at", "updated_at", "id_car", "id_service_type", "id_service_edmunds", "id_service_customized", "id_recall_recallmasters", "id_service_archive", "id_service_mmy", "id_service_preset", "id_dtc", "dtc_is_pending" FROM "car_service" AS "car_service" WHERE ("car_service"."id_dtc" = 6 AND "car_service"."id_car" = 95) FOR UPDATE;

undefined
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有谁知道为什么我仍然在表中添加 2 个相同的行，我认为行锁应该阻止具有选择更新的事务？

Answer 1

您必须在交易的第二个查询中传入相应的交易对象 {transaction: t1} 或 {transaction: t2} 作为选项。

引用示例 ( in the documentation )