我有表report_data
,它属于daily_entry
表,但是当我调用api来获取daily_entry
表的所有数据时,它会发送响应像下面这样
输出
{
"response_code": "0",
"message": "Operation is successfully executed",
"status": "success",
"data": {
"id": 1,
"user_id": 1,
"date": "12-10-2020",
other data ....
"is_active": true,
"createdAt": "2020-10-21T06:25:57.877Z",
"updatedAt": "2020-10-21T06:25:57.877Z",
"report_datum": {
"id": 1,
"entry_id": 1,
"Date": null,
"report_document_id": "2",
"createdAt": "2020-10-21T06:26:02.642Z",
"updatedAt": "2020-10-21T06:26:02.642Z"
}
},
"level": "info",
"timestamp": "2020-10-21T06:25:45.947Z"
}
预计
{
"response_code": "0",
"message": "Operation is successfully executed",
"status": "success",
"data": {
"id": 1,
"user_id": 1,
"date": "12-10-2020",
other data ....
"is_active": true,
"createdAt": "2020-10-21T06:25:57.877Z",
"updatedAt": "2020-10-21T06:25:57.877Z",
"report_data": {
"id": 1,
"entry_id": 1,
"Date": null,
"report_document_id": "2",
"createdAt": "2020-10-21T06:26:02.642Z",
"updatedAt": "2020-10-21T06:26:02.642Z"
}
},
"level": "info",
"timestamp": "2020-10-21T06:25:45.947Z"
}
我检查了我的整个项目,没有像report_datum
这样的名称,是sequelize.js的错误还是有其他方法
API I 代码如下
getdaily_entryById: async (req, res) => {
sequelize.sequelize.transaction(async (t1) => {
if (!req.params.id) {
logger.warn(error.MANDATORY_FIELDS)
return res.status(500).send(error.MANDATORY_FIELDS);
}
let data = await sequelize.daily_entry.findOne({
where: { id: req.params.id },
include: [
sequelize.report_data
]
});
let result = error.OK
result.data = data
logger.info(result);
return res.status(200).send(result);
}).catch(function (err) {
logger.warn(err)
console.log(err)
return res.status(500).send(error.SERVER_ERROR);
});
},
我已经使用了卡住表名称,但名称仍然更改
var db_instance = new Sequelize(config.DB.database, config.DB.username, config.DB.password, {
host: config.DB.host,
dialect: config.DB.dialect,
define: {
timestamps: true,
freezeTableName: true
},
logging: false
});
更新
每日条目表
module.exports = function (sequelize, DataTypes) {
const daily_entry = sequelize.define('daily_entry ', {
user_id: {
type: DataTypes.INTEGER(),
allowNull: true
},
date: {
type: DataTypes.STRING,
allowNull: true
},
report_status: {
type: DataTypes.STRING,
allowNull: true
},
high_close: {
type: DataTypes.DOUBLE(),
allowNull: true
},
high_open: {
type: DataTypes.DOUBLE(),
allowNull: true
},
low_close: {
type: DataTypes.DOUBLE(),
allowNull: true
},
low_open: {
type: DataTypes.DOUBLE(),
allowNull: true
},
is_active: {
type: DataTypes.BOOLEAN,
allowNull: true
}
});
return daily_entry
};
报告数据
module.exports = function (sequelize, DataTypes) {
const report_data= sequelize.define('report_data', {
daily_entry : {
type: DataTypes.INTEGER(),
allowNull: true
},
Date: {
type: DataTypes.INTEGER(),
allowNull: true
},
report_document_id: {
type: DataTypes.TEXT,
allowNull: true
}
},
{
tableName: 'report_data'
});
return report_data
};
最佳答案
你能试试这个吗?希望能解决您的问题
let data = await sequelize.daily_entry.findOne({
where: { id: req.params.id },
include: [
{
model:sequelize.report_data,
as:'report_data',
required:true
}
]
});
关于node.js - 从sequelize.js获取错误的对象名称,包括从数据到数据的JSON响应中的方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/64457909/