ruby-on-rails - 具有不同名称的 FactoryGirl 协会

Question

我有以下关联

class Training < ApplicationRecord
  has_many :attendances
  has_many :attendees, through: :attendances
end

class Attendance < ApplicationRecord
  belongs_to :training
  belongs_to :attendee, class_name: 'Employee'

考勤表有attendee_id和 training_id .

现在，我如何创建一个有效的 Attendance和工厂女郎？

目前，我有以下代码

FactoryGirl.define do
  factory :attendance do
    training
    attendee
  end
end

FactoryGirl.define do
  factory :employee, aliases: [:attendee] do
    sequence(:full_name) { |n| "John Doe#{n}" }
    department
  end
end

但我得到

  NoMethodError:
       undefined method `employee=' for #<Attendance:0x007f83b163b8e8>

我也试过

FactoryGirl.define do
  factory :attendance do
    training
    association :attendee, factory: :employee
  end
end

同样的结果。

感谢您的帮助(或者在 SO 上不允许有礼貌？？？)。

Answer 1

您可能知道 FactoryGirl 使用符号来推断类是什么，但是当您为同一模型创建另一个具有不同符号的工厂时，您需要告诉 FactoryGirl 要使用的类是什么:

FactoryGirl.define do
  factory :attendance do
    training = { FactoryGirl.create(:training) }
    attendee = { FactoryGirl.create(:employee) }
  end
end

FactoryGirl.define do
  factory :employee, class: Attendee do
    sequence(:full_name) { |n| "John Doe#{n}" }
    department
  end
end

或者可以手动分配关系(例如，如果您不希望此时将员工实例保存到数据库中):

FactoryGirl.build(:attendance, attendee: FactoryGirl.build(:employee))