javascript - typescript :使用联合类型映射对象值无法按预期工作

Question

如果我想映射所有值都是基元的对象值，这非常简单:

type ObjectOf<T> = { [k: string]: T };

type MapObj<Obj extends ObjectOf<any>> = {
  [K in keyof Obj]: Obj[K] extends string ? Obj[K] : 'not string';
};

type Foo = MapObj<{
  a: 'string',
  b: 123,
}>; // Foo is { a: 'string', b: 'not string' }

但是，当我将联合作为对象值时，TS 不会按预期工作:

type AllPaths = '/user' | '/post';

type Props<Path extends AllPaths> = MapObj<{
  path: Path,
}>;

function Fn<Path extends AllPaths>({ path }: Props<Path>) {
  const path2: AllPaths = path;
}

我收到错误:

Type 'Path extends string ? Path : "not string"' is not assignable to type 'AllPaths'.
  Type 'Path | "not string"' is not assignable to type 'AllPaths'.
    Type '"not string"' is not assignable to type 'AllPaths'.
      Type 'Path extends string ? Path : "not string"' is not assignable to type '"/post"'.
        Type 'Path | "not string"' is not assignable to type '"/post"'.
          Type 'string & Path' is not assignable to type '"/post"'.

由于联合的每个成员都是字符串，我预计 MapObj 的输出保持字符串的联合。我怎样才能解决这个问题？
TS游乐场:https://www.typescriptlang.org/play?#code/C4TwDgpgBA8gRgKwgY2DAZgHgCoD4oC8UA3lANoDWAXFAM7ABOAlgHYDmAujdlAL4DcAKEGhIUALIBDMPASZZUCAA9gEFgBNasRCjRZJLELnxFigqOQDSUVlAoQQAe3TaEXV2UsdFKtZrqMrGxQAPweXlA0AOQsjsABzOxRQgLCotAAggA2WQAKksAAFlpEUQD0AK60EAxRUAA+UOVgjvTJaeDQuQyOYLSY+UU+qhpa2XkFxSYS0rKYZhZgkzSDhQA0gry4QoLoFSyoTI4sUABiLAOTw35jOau0uAAUpEtDvCs9fZdFuACUJOYoMhjvQoK9CgAmGjje6EMGTFKCIA

Answer 1

我认为问题是即使你声明 type Props<Path extends AllPaths> = MapObj<{ path: Path, }>;像这样，它将只包含值 '/user' | '/post' ，但这种知识可能无法被 typescript 静态类型检查识别，因为它的类型是 MapObj<{ path: Path, }>这只是一个 js 对象的 MapObj。
所以只需使用 as Path妥协

function Fn<Path extends AllPaths>({ path }: Props<Path>) {
  const path2: AllPaths = path as Path;
}

或者像这样为 PathObj 声明一个类型:

type AllPaths = '/user' | '/post';
type AllPathObj = {
  path: AllPaths,
}

type Props<PathObj extends AllPathObj> = MapObj<AllPathObj>;

function Fn<PathObj extends AllPathObj>({ path }: Props<PathObj>) {
  const path2: AllPaths = path;
}