这个问题在这里已经有了答案:
Rest Template custom exception handling
(2 个回答)
4年前关闭。
是否可以在不使用异常的情况下使用 Spring RestTemplate 来处理状态为 500 的 http 响应?
RestTemplate restTemplate = new RestTemplate();
try {
response = restTemplate.getForEntity(probe.getUrl(), String.class);
boolean isOK = response.getStatusCode() == HttpStatus.OK;
// would be nice if 500 would also stay here
}
catch (HttpServerErrorException exc) {
// but seems only possible to handle here...
}
最佳答案
您可以使用注释创建 Controller @ControllerAdvice
如果您使用 springmvc。在 Controller 中写:
@ExceptionHandler(HttpClientErrorException.class)
public String handleXXException(HttpClientErrorException e) {
log.error("log HttpClientErrorException: ", e);
return "HttpClientErrorException_message";
}
@ExceptionHandler(HttpServerErrorException.class)
public String handleXXException(HttpServerErrorException e) {
log.error("log HttpServerErrorException: ", e);
return "HttpServerErrorException_message";
}
...
// catch unknown error
@ExceptionHandler(Exception.class)
public String handleException(Exception e) {
log.error("log unknown error", e);
return "unknown_error_message";
}
和
DefaultResponseErrorHandler
抛出这两种异常:@Override
public void handleError(ClientHttpResponse response) throws IOException {
HttpStatus statusCode = getHttpStatusCode(response);
switch (statusCode.series()) {
case CLIENT_ERROR:
throw new HttpClientErrorException(statusCode, response.getStatusText(),
response.getHeaders(), getResponseBody(response), getCharset(response));
case SERVER_ERROR:
throw new HttpServerErrorException(statusCode, response.getStatusText(),
response.getHeaders(), getResponseBody(response), getCharset(response));
default:
throw new RestClientException("Unknown status code [" + statusCode + "]");
}
}
您可以使用:
e.getResponseBodyAsString();
, e.getStatusCode();
blabla 在 Controller 建议中在异常发生时获取响应消息。
关于如果 Http 状态为 500,Spring RestTemplate 总是抛出异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31728111/