我目前正在尝试用 turtle 在 python 中绘制一个 Mandelbrot 集。但是,我的问题与 Mandelbrot 无关。我无法更改 turtle 窗口的大小。我怎样才能做到这一点?
我尝试初始化屏幕并使用 screensize 方法设置屏幕大小。如果我这样做,什么都不会改变。
这是我绘制集合的代码。我粘贴了整个代码,因为我不知道我做错了什么,屏幕尺寸没有改变。
from turtle import *
height = 360
width = 360
screen = Screen()
screen.screensize(width, height)
tu = Turtle()
tu.hideturtle()
tu.speed(0)
tu.penup()
def decreasePoint(n, start1, stop1, start2, stop2):
return ((n - start1) / (stop1 - start1)) * (stop2 - start2) + start2
for x in range(width):
for y in range(height):
a = decreasePoint(x, 0, width, -2, 2)
b = decreasePoint(y, 0, height, -2, 2)
ca = a
cb = b
n = 0
z = 0
while n < 100:
aa = a * a - b * b
bb = 2 * a * b
a = aa + ca
b = bb + cb
n += 1
if abs(a + b) > 16:
break
bright = 'pink'
if (n == 100):
bright = 'black'
tu.goto(x , y)
tu.pendown()
tu.dot(4, bright)
tu.penup()
done()
最佳答案
代替:
screen.screensize(width, height)
做:
screen.setup(width, height)
screensize()
方法设置 turtle 可以漫游的区域量,但不改变屏幕大小(尽管名称),只是可滚动区域。此外,为了简化您的代码,加快速度并产生更详细的结果,我建议进行以下返工:from turtle import Screen, Turtle
WIDTH, HEIGHT = 360, 360
screen = Screen()
screen.setup(WIDTH + 4, HEIGHT + 8) # fudge factors due to window borders & title bar
screen.setworldcoordinates(0, 0, WIDTH, HEIGHT)
turtle = Turtle()
turtle.hideturtle()
turtle.penup()
def scalePoint(n, start1, stop1, start2, stop2):
return (n - start1) * (stop2 - start2) / (stop1 - start1) + start2
screen.tracer(False)
for x in range(WIDTH):
real = scalePoint(x, 0, WIDTH, -2, 2)
for y in range(HEIGHT):
imaginary = scalePoint(y, 0, HEIGHT, -2, 2)
c = complex(real, imaginary)
z = 0j
color = 'pink'
for _ in range(100):
if abs(z) >= 16.0:
break
z = z * z + c
else:
color = 'black'
turtle.goto(x, y)
turtle.dot(1, color)
screen.update()
screen.tracer(True)
screen.exitonclick()
关于python - 如何更改 python turtle 窗口的大小?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56528067/