如何检查字符串是否为 严格包含字母和数字?
跟随还不够?
def containsLettersAndNumber(input):
if input.isalnum():
return True
else:
return False
isAlnum = containsLettersAndNumber('abc') # Should return false
isAlnum = containsLettersAndNumber('123') # Should return false
isAlnum = containsLettersAndNumber('abc123') # Should return true
isAlnum = containsLettersAndNumber('abc123$#') # Should return true
请注意它必须包含字母和数字
最佳答案
您可以循环并跟踪您是否找到了一个字母以及是否找到了一个数字:
def containsLetterAndNumber(input):
has_letter = False
has_number = False
for x in input:
if x.isalpha():
has_letter = True
elif x.isnumeric():
has_number = True
if has_letter and has_number:
return True
return False
或者,一种更pythonic但更慢的方式:def containsLetterAndNumber(input):
return any(x.isalpha() for x in input) and any(x.isnumeric() for x in input)
关于python - 如何检查字符串是否严格包含字母和数字,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/64862663/