reactjs - 设置连接的 React 路由器

Question

我正在尝试根据 t he steps in the README 设置连接 react 路由器.

我的 store.js 中有这个当前代码:

import { createStore } from 'redux';
import reducer from './reducers';
import { middleware, runSagas } from './middleware';

const createSWStore = () => {
  const store = createStore(reducer, middleware);
  runSagas();
  return store;
};

export default createSWStore;

我试图按照设置进行操作，但我不断收到 Uncaught TypeError: rootReducer is not a function浏览器中的错误。

目前该文件如下所示:

import { createBrowserHistory } from 'history';
import { applyMiddleware, compose, createStore } from 'redux';
import { connectRouter, routerMiddleware } from 'connected-react-router';

import reducer from './reducers';
import { middleware, runSagas } from './middleware';

const history = createBrowserHistory();

const createSWStore = () => {
  const store = createStore(
    connectRouter(reducer)(history),
    compose(
      applyMiddleware(
        routerMiddleware(history),
      ),
    ),
    middleware);
  runSagas();
  return store;
};

export default createSWStore;

Answer 1

给 connectRouter history而不是 reducer 。所以:

connectRouter(history)(reducer),

而不是 connectRouter(reducer)(history) .

你说的是import reducer from './reducers';指的是一个包含 reducer 的文件夹。假设 reducers 文件夹有三个文件(index.js、reducer1.js 和 reducer2.js)，那么在 reducers 中有这样的东西应该管用:

Index.js

import reducer1 from './reducer1';
import reducer2 from './reducer2';
import { combineReducers } from 'redux';

export default combineReducers({ reducer1, reducer2 });

reducer1.js

const reducer1 = (state = { myState: "foo" }, action) => {
    return state;
};

export default reducer1;

reducer2.js

const reducer2 = (state = { myState: "bar" }, action) => {
    return state;
};

export default reducer2;