ios - Flutter - 代码签名 "App.framework"失败

Question

我是 Flutter 的新手，并试图在 iOS 上实现我的第一个应用程序，但是，我正面临这个问题，并从上周开始尝试解决它。​​

1.运行“flutter build ios”后，构建签名成功

2.项目存档也成功

(问题) 但是当我点击验证应用程序时。我遇到了以下问题，我花了很多时间并进行了大量调试，但找不到导致此问题的原因。

错误信息截图

终端输出:flutter doctor -v

[✓] Flutter (Channel stable, 1.22.3, on Mac OS X 10.15.7 19H2, locale en-GB)
• Flutter version 1.22.3 at /Users/sohumwahi/Library/flutter
• Framework revision 8874f21 (6 days ago), 2020-10-29 14:14:35 -0700
• Engine revision a1440ca392
• Dart version 2.10.3

[✓] Android toolchain - develop for Android devices (Android SDK version 30.0.2)
• Android SDK at /Users/sohumwahi/Library/Android/sdk
• Platform android-30, build-tools 30.0.2
• Java binary at: /Applications/Android
Studio.app/Contents/jre/jdk/Contents/Home/bin/java
• Java version OpenJDK Runtime Environment (build
1.8.0_242-release-1644-b3-6222593)
• All Android licenses accepted.

[✓] Xcode - develop for iOS and macOS (Xcode 12.1)
• Xcode at /Applications/Xcode.app/Contents/Developer
• Xcode 12.1, Build version 12A7403
• CocoaPods version 1.10.0

[!] Android Studio (version 4.1)
• Android Studio at /Applications/Android Studio.app/Contents
✗ Flutter plugin not installed; this adds Flutter specific functionality.
✗ Dart plugin not installed; this adds Dart specific functionality.
• Java version OpenJDK Runtime Environment (build
1.8.0_242-release-1644-b3-6222593)

[✓] VS Code (version 1.50.1)
• VS Code at /Applications/Visual Studio Code.app/Contents
• Flutter extension version 3.16.0

[✓] Connected device (1 available)
• iPhone 11 Pro (mobile) • 093FA4C3-39F3-4D69-B945-DDD155FDBD49 • ios •
com.apple.CoreSimulator.SimRuntime.iOS-14-1 (simulator)

! Doctor found issues in 1 category.

Answer 1

以下是解决此错误的方法: 您必须将脚本添加到您的 xcode 中，以删除第三方库中未使用的代码。 当你在 xcode 中打开你的 flutter iOS 项目时，你会在构建阶段部分看到 flutter 已经有了一个脚本。不要弄乱这个脚本，相反你会添加一个新的。 就像这张图片:

然后你会得到这样的东西:

在此之后打开运行脚本并放置此代码:

# Type a script or drag a script file from your workspace to insert its path.APP_PATH="${TARGET_BUILD_DIR}/${WRAPPER_NAME}"
# This script loops through the frameworks embedded in the application and
# removes unused architectures.

find "$APP_PATH" -name 'FRAMEWORK_NAME*.framework' -type d | while read -r
FRAMEWORK
do
FRAMEWORK_EXECUTABLE_NAME=$(defaults read "$FRAMEWORK/Info.plist" CFBundleExecutable)
FRAMEWORK_EXECUTABLE_PATH="$FRAMEWORK/$FRAMEWORK_EXECUTABLE_NAME"echo "Executable is $FRAMEWORK_EXECUTABLE_PATH"

EXTRACTED_ARCHS=()

for ARCH in $ARCHS
do
echo "Extracting $ARCH from $FRAMEWORK_EXECUTABLE_NAME"
lipo -extract "$ARCH" "$FRAMEWORK_EXECUTABLE_PATH" -o
"$FRAMEWORK_EXECUTABLE_PATH-$ARCH"
EXTRACTED_ARCHS+=("$FRAMEWORK_EXECUTABLE_PATH-$ARCH")
done

echo "Merging extracted architectures: ${ARCHS}"
lipo -o "$FRAMEWORK_EXECUTABLE_PATH-merged" -create
"${EXTRACTED_ARCHS[@]}"
rm "${EXTRACTED_ARCHS[@]}"

echo "Replacing original executable with thinned version"
rm "$FRAMEWORK_EXECUTABLE_PATH"
mv "$FRAMEWORK_EXECUTABLE_PATH-merged" "$FRAMEWORK_EXECUTABLE_PATH"

done

如果您遇到指出脚本中存在语法错误的错误，请尝试删除在您尝试复制脚本时可能已复制的无法识别的字符 因为 xcode 不处理它们而且它发生在我身上。因此，复制代码并将其放置在能够处理此类字符的不同代码编辑器中(例如 visual studio)，然后从某些行的末尾删除不需要的字符。 所以现在总共有两个脚本在运行