查看 W3 Schools URL encoding webpage ,它说 @
应该编码为 %40
,而 space
应该编码为 %20
。
URLEncoder
和 URI
我都试过了,但是上面的都没有:
import java.net.URI;
import java.net.URLEncoder;
public class Test {
public static void main(String[] args) throws Exception {
// Prints me%40home.com (CORRECT)
System.out.println(URLEncoder.encode("me@home.com", "UTF-8"));
// Prints Email+Address (WRONG: Should be Email%20Address)
System.out.println(URLEncoder.encode("Email Address", "UTF-8"));
// http://www.home.com/test?Email%20Address=me@home.com
// (WRONG: it has not encoded the @ in the email address)
URI uri = new URI("http", "www.home.com", "/test", "Email Address=me@home.com", null);
System.out.println(uri.toString());
}
}
出于某种原因,URLEncoder
正确输入电子邮件地址但不输入空格,URI
正确输入货币但不输入电子邮件地址。
我应该如何对这两个参数进行编码以与 w3schools 所说的正确(或者 w3schools 错误?)一致
最佳答案
虽然我认为来自@fge 的答案是正确的,因为我使用的是依赖于 W3Schools 文章中概述的编码的第 3 方网络服务,但我遵循了来自 Java equivalent to JavaScript's encodeURIComponent that produces identical output? 的答案。
public static String encodeURIComponent(String s) {
String result;
try {
result = URLEncoder.encode(s, "UTF-8")
.replaceAll("\\+", "%20")
.replaceAll("\\%21", "!")
.replaceAll("\\%27", "'")
.replaceAll("\\%28", "(")
.replaceAll("\\%29", ")")
.replaceAll("\\%7E", "~");
} catch (UnsupportedEncodingException e) {
result = s;
}
return result;
}
关于Java URL 编码 : URLEncoder vs. URI,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14321873/