我正在实现一个 JavaFX 应用程序,它通过 wifi (android) 与手机通信。
因此,我在 JavaFX 上有一个服务器线程在后台进程中运行:
public class NetworkService implements Runnable {
private final ServerSocket serverSocket;
private final ExecutorService pool;
private RoutePlannerJFX application;
private UserData userData;
public NetworkService(ExecutorService pool,
ServerSocket serverSocket,
RoutePlannerJFX app,
UserData data) {
this.serverSocket = serverSocket;
this.pool = pool;
application = app;
userData = data;
}
public void run() {
try {
while ( true ) {
Socket cs = serverSocket.accept();
pool.execute(new Handler(serverSocket, cs, application, userData));
}
} catch (IOException ex) {
System.out.println("--- Interrupt NetworkService-run");
}
finally {
System.out.println("--- Ende NetworkService(pool.shutdown)");
pool.shutdown(); //keine Annahme von neuen Anforderungen
try {
pool.awaitTermination(4L, TimeUnit.SECONDS);
if ( !serverSocket.isClosed() ) {
System.out.println("--- Ende NetworkService:ServerSocket close");
serverSocket.close();
}
} catch ( IOException e ) { }
catch ( InterruptedException ei ) { }
}
}
}
它有一个处理程序:
public class Handler implements Runnable {
private final Socket client;
private final ServerSocket serverSocket;
private RoutePlannerJFX application;
private UserData userData;
Handler(ServerSocket serverSocket,Socket client, RoutePlannerJFX app, UserData data) {
this.client = client;
this.serverSocket = serverSocket;
application = app;
userData = data;
}
public void run() {
StringBuffer sb = new StringBuffer();
PrintWriter out = null;
try {
System.out.println( "running service, " + Thread.currentThread() );
out = new PrintWriter( client.getOutputStream(), true );
BufferedReader bufferedReader =
new BufferedReader(
new InputStreamReader(
client.getInputStream()));
char[] buffer = new char[100];
int anzahlZeichen = bufferedReader.read(buffer, 0, 100);
String nachricht = new String(buffer, 0, anzahlZeichen);
String[] werte = nachricht.split("\\s");
System.out.println(nachricht+"\n");
POI poi = new POI(nachricht);
userData.addItemToPoiList(poi);
application.setScene("INSTRUCT");
} catch (IOException e) {System.out.println("IOException, Handler-run");}
finally {
System.out.println(sb); //Rückgabe Ergebnis an den Client
if ( !client.isClosed() ) {
System.out.println("****** Handler:Client close");
try {
client.close();
} catch ( IOException e ) { }
}
}
}
}
应用程序有一个公共(public)方法来更改场景 (setScene())。
这就是我希望能够做到的方式,但现在我知道,我无法在后台进程中切换场景。
有人知道如何解决这个问题吗?当我的后台进程收到来自客户端的消息时,我需要触发一个操作,但我不知道最好的方法是什么......我已经找到了 javafx.concurrent,但我必须使用哪个以及如何使用?
提前致谢!
最佳答案
对于客户端,您可以使用任务或服务在单独的线程中运行并更新 GUI,如 documentation 中所述。
你也可以查看这篇文章JavaFX Async Task
关于multithreading - 使用 javafx.concurrent 的 JavaFX 网络后台任务,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12239664/