python - 如何使 pynput.keyboard 作为线程运行？

Question

我使用 Pynput 编写了一个脚本来捕获击键，一切顺利，直到我想在捕获击键(线程)时每 15 秒截取一次屏幕截图。

我阅读了有关 pynput.keyboard 的文档，发现键盘监听器是一个 threading.Thread，但我无法做到这一点，我想我设法创建了两个线程，但它没有进入“getKey”函数我不知道为什么。

from PIL import ImageGrab
import time 
from pynput.keyboard import Key, Listener
from pynput import keyboard
import logging
import os 
import threading


def main():
    listener = keyboard.Listener(onpress=getKey)
    listener.start()
    thread2 = threading.Thread(target=takeScreenshot, args=())
    thread2.start()
    thread2.join()


def getKey(key):
    print(key)
    key = fixKey(key)
    file = open('log.txt', 'a')
    file.write(key.replace('\'', '') + '')
    file.close()

def fixKey(key):
    key = str(key)
    if key == 'Key.space':
        return ' '
    elif key == 'Key.enter':
        return '\n'
    return key

def takeScreenshot():
    time.sleep(15)
    image = ImageGrab.grab()
    now = time.strftime("%d-%m-%Y" + ' ' + "%H-%M-%S")
    image.save(now + '.png')

main()

正如我所解释的，它甚至不会创建文件“log.txt”，只会在 15 秒后截取屏幕截图。 谢谢!

Answer 1

官方的监听器的正确使用方法docs

如果您需要每 15 秒捕获一次屏幕截图，您应该运行一个带有 while 循环的线程，以便在后台连续运行

这是代码:

from PIL import ImageGrab
import time 
from pynput.keyboard import Key, Listener
from pynput import keyboard
import logging
import os 
import threading


def main():
    thread2 = threading.Thread(target=takeScreenshot, args=())
    thread2.start()

    with Listener(on_press=getKey) as listener:
        listener.join()


def getKey(key):
    print(key)
    key = fixKey(key)
    file = open('log.txt', 'a')
    file.write(key.replace('\'', '') + '')
    file.close()

def fixKey(key):
    key = str(key)
    if key == 'Key.space':
        return ' '
    elif key == 'Key.enter':
        return '\n'
    return key

def takeScreenshot():
    # run contineous and take screenshot every 15 seconds
    while True:
        print('taking screenshot')
        image = ImageGrab.grab()
        now = time.strftime("%d-%m-%Y" + ' ' + "%H-%M-%S")
        image.save(now + '.png')
        time.sleep(15)


main()