javascript - 可选链接 - Function.prototype.apply 在未定义时调用，这是未定义而不是函数

Question

Using optional chaining with function calls causes the expression to automatically return undefined instead of throwing an exception if the method isn't found.

注意:代码使用 spread syntax ，而不是 rest parameters .

const fn1 = undefined
const args = []
const fn2 = () => {}
const fn3 = () => {}

console.log(fn1?.(...args, fn2, fn3))

错误:

console.log(fn1?.(...args, fn2, fn3))
                                ^
TypeError: Function.prototype.apply was called on undefined, which is an undefined and not a function

Answer 1

原来是V8的bug，我已经提交了there ，希望它会尽快修复。
更新:it has been fixed .