perl - 如何使用快速 Playground 实现套接字连接?

标签 perl sockets swift-playground home-automation

我有这个简单的Perl软件,可以监视我的家庭自动化总线的 Activity ,并在灯光改变其状态时“说”。我想在Xcode操场上使用Swift语言实现它。有什么解决办法吗?

#!/usr/bin/perl -w
#
use strict;
use IO::Socket::INET;
my $mh200ip = "10.0.1.82";
my $ownport = "20000";
my $frames;
my $socket = IO::Socket::INET->new(
    PeerAddr => $mh200ip,
    PeerPort => $ownport,
    Proto    => "tcp",
    Type     => SOCK_STREAM
);
die "Could not create socket: $!\n" unless $socket;
$socket->send("*99*1##");    # Sending OPEN ACK

while (1) {
    $socket->recv( $frames, 128 );
    if ( $frames ne '' ) {
        print "$frames\n";
        my $data = ($frames);
        my @values = split( '##', $data );
        if ( $data eq "*1*0*53##" ) {
            `say "light off"`;
        }
        if ( $data eq "*1*1*53##" ) {
            `say "light on"`;
        }
    } else {
        print "server closed connection";
        exit 1;
    }
}

最佳答案

这是Perl片段到Swift的几乎口头翻译:

#!/usr/bin/swift
import Foundation

func say(whatToSay: String) {
    let task = NSTask()
    task.launchPath = "/usr/bin/say"
    task.arguments = [whatToSay]
    task.launch()
}

let addr = "127.0.0.1"
let port = 2000

var buffer = [UInt8](count: 255, repeatedValue: 0)

var inp : NSInputStream?
var out : NSOutputStream?

NSStream.getStreamsToHostWithName(addr, port: port, inputStream: &inp, outputStream: &out)

if inp != nil && out != nil {
    let inputStream : NSInputStream = inp!
    let outputStream : NSOutputStream = out!
    inputStream.open()
    outputStream.open()

    if outputStream.streamError == nil && inputStream.streamError == nil {
        let queryString: String = "*99*1##"
        let queryData: NSData = queryString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)!
        while true {
            outputStream.write(UnsafePointer(queryData.bytes),maxLength:queryData.length)
            var readChars: Int = inputStream.read(&buffer, maxLength: buffer.count)
            if (readChars > 0) {
                let readString: String = NSString(data: NSData(bytes:buffer, length:readChars), encoding: NSUTF8StringEncoding)!
                if readString == "*1*0*53##" {
                    say("Light off")
                } else if readString == "*1*1*53##" {
                    say("Light on")
                }
            } else {
                println ("server closed connection")
                inputStream.close()
                outputStream.close()
                break
            }
        }
    } else {
        println ("could not create socket")
    }
} else {
    println ("could not initialize stream")
}

关于perl - 如何使用快速 Playground 实现套接字连接?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26625373/

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