c - 如何打印结构体timeVal

Question

我的代码中有这一行

`printf("Rcvd pkt from %s:%d at <%ld.%06ld>\n", inet_ntoa(servAddr.sin_addr),  ntohs(servAddr.sin_port), timeVal.tv_sec, timeVal.tv_usec);`

这是我在编译 gcc 时收到的警告

`cc1: warnings being treated as errors
`client12.c: In function ‘main’:
`client12.c:131: warning: format ‘%06ld’ expects type ‘long int’, but argument 5 has type ‘__darwin_suseconds_t’
`client12.c:131: warning: format ‘%06ld’ expects type ‘long int’, but argument 5 has type ‘__darwin_suseconds_t’

我做错了什么？

PS - 我已经包含了 time.h 和 sys/time.h

Answer 1

将数字转换为正确的类型:

printf("Rcvd pkt from %s:%d at <%ld.%06ld>\n", inet_ntoa(servAddr.sin_addr),  ntohs(servAddr.sin_port), (long int)(timeVal.tv_sec), (long int)(timeVal.tv_usec));