image - 如何在Rust中从摄像头捕获的图像灰度图像

Question

Rust在这里是全新的。我正在尝试使相机从camera_capture lib(基于rscam)中获取图像。当我尝试去做

grayscale(&frame)

它显示了这样的错误:

error[E0277]: the trait bound `camera_capture::Frame: DerefMut` is not satisfied
  --> src/main.rs:22:31
   |
22 |         let frame = grayscale(&frame);
   |                               ^^^^^^ the trait `DerefMut` is not implemented for `camera_capture::Frame`
   |
   = note: required because of the requirements on the impl of `GenericImage` for `ImageBuffer<Rgb<u8>, camera_capture::Frame>`

这是完整的代码:

 extern crate camera_capture;
 extern crate ncurses;
 extern crate image;
 
 use image::imageops::resize;
 use image::imageops::colorops::grayscale;
 use image::FilterType;
 use image::load_from_memory;
 
 
 
 const ASCII_GREYSCALE: &str = "$@B%8&WM#*oahkbdpqwmZO0QLCJUYXzcvunxrjft/\\|()1{}[]?-_+~<>i!lI;:,\"^`'.";
 
 fn main() {
     let cam = camera_capture::create(0).unwrap();
     let mut cam = cam.fps(30.0).unwrap().start().unwrap();
     let window = ncurses::initscr();
     let mut x: i32 = 0;
     let mut y: i32 = 0;
     ncurses::getmaxyx(window, &mut y, &mut x);
     for frame in cam {
         let frame = grayscale(&frame);                                                                                            
         let frame = resize(&frame, x as u32, y as u32, FilterType::Nearest);
         for (i, pixel) in frame.enumerate_pixels().enumerate() {
             let dupa = pixel.2.data;
             let value = (ASCII_GREYSCALE.len() - 1) * dupa[0] as usize/255 + 1;
             let put_y = (i as i32+1)/x;
             let put_x = i as i32 % x;
             let ch = ASCII_GREYSCALE.chars().rev().nth(value).unwrap() as u32;
             ncurses::mvaddch(put_y, put_x, ch);
         }
         ncurses::refresh();
     }
 }

有人知道如何将其转换为灰度吗？也许其他图书馆？

Answer 1

好的，我已经找到了解决方案。可以使用以下命令将其转换为普通图像:: DynamicImage子类型:

let frame = RgbImage::from_raw(frame.width(), frame.height(), frame.to_vec()).unwrap();

然后有可能:

grayscale(&frame)