单击每个人时，该人的下属列表应显示在底部。整个列表是动态的。
{
"EmployeeId": "1",
"Name": "John",
"Position": "HR",
"Image": "",
"SubordinateCount": 6,
"Subordinates": [
{
"EmployeeId": "2",
"Name": "Sub john 1",
"Position": "Manager",
"Image": "",
"SubordinateCount": 1,
"Subordinates": [
{
"EmployeeId": "3",
"Name": "Joseph",
"Position": "Admin",
"Image": "",
"SubordinateCount": 1,
"Subordinates": [
{
"EmployeeId": "4",
"Name": "Raj",
"Position": "Software Developer",
"Image": "",
"SubordinateCount": 0,
"Subordinates": []
}
]
}
]
},
{
"EmployeeId": "5",
"Name": "Rahul",
"Position": "ERP Consultant",
"Image": "",
"SubordinateCount": 16,
"Subordinates": [
{
"EmployeeId": "6",
"Name": "Fam",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "7",
"Name": "Salman A Q",
"Position": "Software Developer",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "8",
"Name": "Mac",
"Position": "Software Developer",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "9",
"Name": "Mathew",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "10",
"Name": "Kim",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "11",
"Name": "Loren",
"Position": "Software Developer",
"Image": "",
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "12",
"Name": "Adam",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "13",
"Name": "Meera",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "14",
"Name": "MMM",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "15",
"Name": "Master",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "16",
"Name": "Michael",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "17",
"Name": "George",
"Position": "Consultant",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "18",
"Name": "Ahmedu A F",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "19",
"Name": "KKKK",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "20",
"Name": "xxx",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "21",
"Name": "DK",
"Position": "QA",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
}
]
},
{
"EmployeeId": "22",
"Name": "HHHH",
"Position": "Engineer",
"Image": "",
"SubordinateCount": 1,
"Subordinates": [
{
"EmployeeId": "23",
"Name": "Ar",
"Position": "Technical",
"Image": "",
"SubordinateCount": 0,
"Subordinates": []
}
]
},
{
"EmployeeId": "24",
"Name": "Sun",
"Position": "Software Developer",
"Image": null,
"SubordinateCount": 1,
"Subordinates": [
{
"EmployeeId": "25",
"Name": "AAAA",
"Position": null,
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
}
]
},
{
"EmployeeId": "26",
"Name": "CCCC",
"Position": "Consultant",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "27",
"Name": "Jaaaa",
"Position": "Software Developer",
"Image": null,
"SubordinateCount": 2,
"Subordinates": [
{
"EmployeeId": "28",
"Name": "Jay",
"Position": "Ssssss",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
},
{
"EmployeeId": "29",
"Name": "NNNN",
"Position": "Sssss",
"Image": null,
"SubordinateCount": 1,
"Subordinates": [
{
"EmployeeId": "30",
"Name": "Jo",
"Position": "Engineer",
"Image": null,
"SubordinateCount": 0,
"Subordinates": []
}
]
}
]
}
]
}
这是我到目前为止所尝试的。
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return selectedIndexes.count + 1
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
var bottomCell : SubordinatesTableViewCell! = self.Extableview.dequeueReusableCell(withIdentifier: "SubordinatesTableViewCell") as? SubordinatesTableViewCell
if bottomCell == nil {
let nib:Array = Bundle.main.loadNibNamed("SubordinatesTableViewCell", owner: self, options: nil)!
bottomCell = nib[0] as? SubordinatesTableViewCell
}
bottomCell.empLevel = indexPath.row
bottomCell.delegate = self
bottomCell.subordinateDetails = self.subordinatesList
return bottomCell
}
extension CurrentVC : SubordinateCellDelegate {
func employeeClicked(row: Int?, index: Int?) {
self.subordinatesList = self.heirarchy?.subordinates
self.currentHeirarchyLevel = row! + 1
if self.Extableview.numberOfRows(inSection: 0) > row! + 1 {
var newIndexes = [Int]()
if row! == 0 {
self.selectedIndexes.removeAll()
self.selectedIndexes.append(index!)
}else {
for i in 0..<(row! + 1) {
newIndexes.append(selectedIndexes[i])
}
self.selectedIndexes = newIndexes
self.selectedIndexes.append(index!)
}
for i in 0..<row! + 1 {
self.subordinatesList = self.subordinatesList?[self.selectedIndexes[i]].subordinates
print(subordinatesList)
}
if subordinatesList?.count ?? 0 > 0 {
self.Extableview.reloadRows(at: [IndexPath(row: self.currentHeirarchyLevel, section: 0)], with: .fade)
}else {
for i in 0..<self.Extableview.numberOfRows(inSection: 0) {
if i > row! {
self.Extableview.beginUpdates()
self.Extableview.deleteRows(at: [IndexPath(row: 1, section: 0)], with: .fade)
}
}
self.numOfsections = row! + 1
self.Extableview.endUpdates()
}
}else {
self.selectedIndexes.append(index!)
for i in 0..<row! + 1 {
self.subordinatesList = self.subordinatesList?[self.selectedIndexes[i]].subordinates
}
if self.subordinatesList?.count ?? 0 > 0 {
self.Extableview.beginUpdates()
self.numOfsections = row! + 2
self.Extableview.insertRows(at: [IndexPath(row: row! + 1, section: 0)], with: .none)
self.Extableview.endUpdates()
}else {
for i in 0..<self.Extableview.numberOfRows(inSection: 0) {
if i > row! {
self.Extableview.beginUpdates()
self.numOfsections = row! + 1
self.Extableview.deleteRows(at: [IndexPath(row: 1, section: 0)], with: .fade)
}
}
self.Extableview.endUpdates()
}
}
}
}
最佳答案
声明4个变量，
var heirarchy : Subordinates?
var numOfRows = 0
var subordinatesList : [Subordinates]?
var subList = [[Subordinates]?]()
self.numOfRows += 1
self.subordinatesList?.append(self.heirarchy!)
self.subList.append([self.heirarchy!])
func employeeClicked(row: Int?, index: Int?, subordinates: [Subordinates]?) {
if (subordinates?.count ?? 0) > 0 {
self.subordinatesList = subordinates
if numOfRows > row! + 2 {
self.tableView.beginUpdates()
for i in (row! + 1)..<tableView.numberOfRows(inSection: 0) {
self.tableView.deleteRows(at: [IndexPath(row: i, section: 0)], with: .fade)
self.numOfRows = numOfRows - 1
self.subList.removeLast()
}
self.subList.append(self.subordinatesList)
self.numOfRows = row! + 2
self.tableView.insertRows(at: [IndexPath(row: row! + 1, section: 0)], with: .fade)
self.tableView.endUpdates()
}
else if numOfRows == row! + 2 {
self.subList[row! + 1] = self.subordinatesList
self.tableView.reloadRows(at: [IndexPath(row: row! + 1, section: 0)], with: .fade)
}else {
self.subList.append(self.subordinatesList)
self.numOfRows = row! + 2
self.tableView.insertRows(at: [IndexPath(row: row! + 1, section: 0)], with: .fade)
}
}else {
if numOfRows > row! + 1 {
self.tableView.beginUpdates()
for i in (row! + 1)..<tableView.numberOfRows(inSection: 0) {
self.tableView.deleteRows(at: [IndexPath(row: i, section: 0)], with: .fade)
self.numOfRows = numOfRows - 1
self.subList.removeLast()
}
self.tableView.endUpdates()
}
}
self.tableView.scrollToBottom()
}
}
希望这可以帮助你。我检查了代码，它对我来说工作正常。
关于ios - 我正在尝试创建层次结构 View 。单击每个人后， View 应展开和收缩，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/65912688/