windows - 如果Windows批处理文件超过一分钟，请立即退出循环

Question

如果满足特定条件，我试图删除Windows服务器上的文件夹。如果不满足，则等待10秒钟然后循环，再次检查条件。我还需要确保我不会永远陷入困境。 (检查我是否在循环中超过60秒，然后退出循环)。批处理文件如下所示:

C:\postgresql\uninstall-postgresql.exe --mode unattended
set TIMESTAMP1=%TIME%
:deleteFolder
tasklist /V |findstr /i "_uninstall*" >nul
if %errorlevel% == 0 (timeout /T /10 >nul
set TIMESTAMP2=%TIME%
**REM I want to make sure that we get out of this loop if the diff b/w TIMESTAMP2 
AND TIMESTAMP1 IS MORE THEN 60 SECONDS**
goto deleteFolder 
) ELSE (
if exists C:\postgresql RD /Q /S C:\postgresql)

Command 1
Command 2
Command 3

因此，我试图从Windows服务器上卸载Postgresql，通过检查任务列表，然后删除basedir(C:\postgresql)，确保卸载完成。如果卸载过程仍在运行，请等待10秒钟，然后再次检查任务列表。我只想确保我不会永远陷入困境。
提前致谢

Answer 1

使用时间戳和calculating time difference:

@echo off
setlocal EnableDelayedExpansion

C:\postgresql\uninstall-postgresql.exe --mode unattended

set "startTime=%time: =0%"
set "endTime="

:deleteFolder
tasklist /V |findstr /i "_uninstall*" >nul
if %errorlevel% == 0 (
    goto waitAndDeleteFolder
) else (
    goto cleanup
)

:waitAndDeleteFolder
timeout /T 10
set "endTime=%time: =0%"
set "end=!endTime:%time:~8,1%=%%100)*100+1!"  &  set "start=!startTime:%time:~8,1%=%%100)*100+1!"
set /A "elap=((((10!end:%time:~2,1%=%%100)*60+1!%%100)-((((10!start:%time:~2,1%=%%100)*60+1!%%100), elap-=(elap>>31)*24*60*60*100"
if !elap! gtr 6000 goto done
goto deleteFolder

:cleanup
if exist "C:\postgresql" RD /Q /S "C:\postgresql"
goto done

:done