在 textField 中搜索的tableView .
我需要从 tableView 中搜索名称.所以我有tableView和 textField在 UIViewController .
我需要从 Api 搜索。为此，我使用了 Alamofire 方法来获取数据。
我需要搜索。现在我实现将 api 中的名称显示到 tableView我得到了输出。但我需要在 mvvm 中实现搜索。如何做.
我的型号:-
class SearchModel: NSObject {
var restaurantname :String!
init?(dictionary :JSONDictionary) {
guard let name = dictionary["name"] as? String else {
return
}
self.restaurantname = name
}
}
我的 View 模型:-
class SearchViewModel: NSObject {
var datasourceModel:SearchDataSourceModel
init(withdatasource newDatasourceModel: SearchDataSourceModel) {
datasourceModel = newDatasourceModel
}
func datafordisplay(atindex indexPath: IndexPath) -> SearchModel{
return datasourceModel.dataListArray![indexPath.row]
}
func numberOfRowsInSection(section:Int) -> Int {
return (datasourceModel.dataListArray?.count)!
}
func loadData(completion :@escaping (_ isSucess:Bool) -> ()){
loadFromWebserviceData { (newDataSourceModel) in
if(newDataSourceModel != nil) {
self.datasourceModel = newDataSourceModel!
completion(true)
}
else {
completion(false)
}
}
}
//}
func loadFromWebserviceData(completion :@escaping (SearchDataSourceModel?) -> ()) {
//with using Alamofire ..............
Alamofire.request("http://www.example.com").validate(statusCode: 200..<300).validate(contentType: ["application/json"]).responseJSON{ response in
switch response.result {
case .success(let data):
print("success",data)
let result = response.result
if let wholedata = result.value as? [String:Any]{
if let data = wholedata["data"] as? Array<[String:Any]>{
// print(data["name"] as! String)
print(data)
print(response)
let newDataSource:SearchDataSourceModel = SearchDataSourceModel(array: data)
completion(newDataSource)
// }
}
}
// case .failure(let data):
// print("fail",data)
case .failure(let encodingError ):
print(encodingError)
// if response.response?.statusCode == 404 {
print(encodingError.localizedDescription)
completion(nil)
// }
}
}}
}
我的数据源模型:-
class SearchDataSourceModel: NSObject {
var dataListArray:Array<SearchModel>? = []
init(array :Array<[String:Any]>?) {
super.init()
var newArray:Array<[String:Any]> = []
if array == nil {
// newArray = self.getJsonDataStored44()
}
else {
newArray = array!
}
var datalist:Array<SearchModel> = []
for dict in newArray {
let model = SearchModel(dictionary: dict)
datalist.append(model!)
}
self.dataListArray = datalist
}
}
我的 viewController 类:-
class SearchViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
@IBOutlet private weak var tableView: UITableView!
private var searchViewModel :SearchViewModel!
init(nibName nibNameOrNil: String?, bundle nibBundleOrNil: Bundle?, withViewModel viewModel:SearchViewModel) {
super.init(nibName: nibNameOrNil, bundle: nibBundleOrNil)
searchViewModel = viewModel
}
required init?(coder aDecoder: NSCoder) {
fatalError("init(coder:) has not been implemented")
}
override func viewDidLoad() {
super.viewDidLoad()
// tableView.dataSource = self
// filteredData = data
searchViewModel.loadData { (isSuccess) in
if(isSuccess == true) {
self.tableView .reloadData()
}
else {
}
}
// self.tableView .reloadData()
// Do any additional setup after loading the view.
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return searchViewModel.numberOfRowsInSection(section: section)
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let identifier = "searchcell"
var cell: SearchCell! = tableView.dequeueReusableCell(withIdentifier: identifier) as? SearchCell
if cell == nil {
tableView.register(UINib(nibName: "SearchCell", bundle: nil), forCellReuseIdentifier: identifier)
cell = tableView.dequeueReusableCell(withIdentifier: identifier) as? SearchCell
}
cell.setsearchData(search: searchViewModel.datafordisplay(atindex: indexPath))
// cell.name.text = searchViewModel.datafordisplay(atindex: indexPath)
// cell.name.text = filteredData[indexPath.row]
// cell.setsearchData(search: searchViewModel.datafordisplay(atindex: indexPath))
return cell
}
/*
// MARK: - Navigation
// In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
// Get the new view controller using segue.destinationViewController.
// Pass the selected object to the new view controller.
}
*/
}
tableViewCell:-
class SearchCell: UITableViewCell {
@IBOutlet weak var name: UILabel!
override func awakeFromNib() {
super.awakeFromNib()
}
override func setSelected(_ selected: Bool, animated: Bool) {
super.setSelected(selected, animated: animated)
}
func setsearchData(search:SearchModel) {
self.name.text = search.restaurantname
}
}
这是我的代码。现在如何在这里实现搜索。
最佳答案
没有搜索的方法。
1的解决方案:
您需要在搜索按钮上调用一个方法
搜索按钮。
func Search() {
predicate = NSPredicate(format: "Self.YourSearchListName beginsWith[c]%@", SearchName)
GetsearchList = YourArrayForSearch.filtered(using: predicate) as NSArray
YourTable.reloadData()
}
第二种解决方案
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
if textField == self.YourTextFieldName{
Search()
}
}
对于第二个解决方案，不要忘记设置委托(delegate)。
关于ios - 在 tableview 的文本字段中搜索，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50094724/