linux - 循环退出并转到bash中的下一行

Question

我想将“配置文件”中的第一行迭代到“arn”中的第一行，然后将第二行“profile”迭代到“arn”中的第二行，将“profile”中的第三行迭代到“arn”中的第三行
但是我的脚本检查了配置文件中的第一个文件，并循环了“arn”文件中的所有内容。完成后，它将到达“配置文件”中的下一行，并在“arn”中循环所有内容

#!/bin/bash

for profile in `cat ../../.aws/config|grep 'profile'`
do
        for arn in `cat policy_arn`
        do
                 aws --profile ${profile} iam delete-policy  --policy-arn ${arn}
        done
done

猫policy_arn

arn:aws:iam::37928052:policy/PointPolicy
arn:aws:iam::56433041:policy/PointPolicy
arn:aws:iam::18225202:policy/PointPolicy
arn:aws:iam::908231278:policy/PointPolicy
arn:aws:iam::441043922:policy/PointPolicy
arn:aws:iam::227661653:policy/PointPolicy

个人资料

dev-ops
pro-ops
qc-ops 

输出值
应该

first loop arn=arn:aws:iam::37928052:policy/PointPolicy and profile=dev-ops
2. arn=arn:aws:iam::56433041:policy/PointPolicy profile=pro-ops
3. arn=arn:aws:iam::18225202:policy/PointPolicy profile=qc-ops

但是当我运行脚本时发生的是

dev-ops arn:aws:iam::37928052:policy/PointPolicy
dev-ops arn:aws:iam::56433041:policy/PointPolicy
dev-ops arn:aws:iam::18225202:policy/PointPolicy
dev-ops arn:aws:iam::908231278:policy/PointPolicy
dev-ops arn:aws:iam::441043922:policy/PointPolicy
dev-ops arn:aws:iam::227661653:policy/PointPolicy


pro-ops arn:aws:iam::37928052:policy/PointPolicy
pro-ops arn:aws:iam::56433041:policy/PointPolicy
pro-ops arn:aws:iam::18225202:policy/PointPolicy
pro-ops arn:aws:iam::908231278:policy/PointPolicy
pro-ops arn:aws:iam::441043922:policy/PointPolicy
pro-ops arn:aws:iam::227661653:policy/PointPolicy

qc-ops arn:aws:iam::37928052:policy/PointPolicy
qc-ops arn:aws:iam::56433041:policy/PointPolicy
qc-ops arn:aws:iam::18225202:policy/PointPolicy
qc-ops arn:aws:iam::908231278:policy/PointPolicy
qc-ops arn:aws:iam::441043922:policy/PointPolicy
qc-ops arn:aws:iam::227661653:policy/PointPolicy

我有40多个aws帐户，因此我将在策略arn应使用相同的配置文件帐户ID的同时为“配置文件”创建一个循环。
我如何实现这样的输出。

Answer 1

您可以执行以下操作:

grep 'profile' ../../.aws/config | paste - policy_arn

paste命令将两个文件作为列联接，在这里，我们使用-作为第一个文件名，以表示它来自stdin(即它来自管道)。无需循环。