php - 提交时出现PHP错误

Question

我试图显示数据库中的2行，但是我希望它是当我单击第一行单选按钮时第一行更新..这没有发生...当我单击第一行时第二行更新了..检查它请自己住---> http://albsocial.us/seria.php

  <?php

 include("connect.php");

    $query = "SELECT * FROM test ORDER BY `id` DESC LIMIT 2";
    $result = mysql_query($query);

    echo "<h2>Seria A</h2><hr/>";

    while($row = mysql_fetch_array($result)){
        $id = $row['id'];
        $home = $row['home'];
        $away = $row['away'];
        $win = $row['win'];
        $draw = $row['draw'];
        $lose = $row['lose'];


        echo $home, " - ", $away,"<br/>";

        echo "<form action='' method='post'>

        <input type='hidden' name='id' value='".$row['id']."'>

        <input type='radio' name='select' value='1'>1
        <input type='radio' name='select' value='X'>X
        <input type='radio' name='select' value='2'>2

        <input type='submit' name='submit' value='Submit'/>

        </form>
        ";

         echo $home, " -> ", $win;
         echo "<br/>Barazim  -> ", $draw,"<br/>";
         echo $away, " -> ", $lose,"<hr/>";
    }   

    $id = isset($_POST['id']) && is_numeric($_POST['id']) ? $_POST['id']:false;

    if (isset($_POST) && $_POST['select'] == 1){
        $select = $_POST['select'];
        $select = $win + $select;
        mysql_query("UPDATE test SET win='$select' WHERE id='$id'");
        header('Location: ../seria.php');
    }else if (isset($_POST) && $_POST['select'] == 'X'){
        $select = $_POST['select'];
        $select = '1';
        $select = $draw + $select;
        mysql_query("UPDATE test SET draw='$select' WHERE id='$id'");
        header('Location: ../seria.php');
    }else if (isset($_POST) && $_POST['select'] == 2){
        $select = $_POST['select'];
        $select = '1';
        $select = $lose + $select;
        mysql_query("UPDATE test SET lose='$select' WHERE id='$id'");
        header('Location: ../seria.php');
    } 

    ?>

Answer 1

问题出在您的按钮名称上。您应该为每个按钮名指定一个不同的名称，以便服务器知道要提交的表单。您可以尝试根据id给出按钮名称，如下所示:

<input type='submit' name='submit<?php echo $id; ?>' value='Submit'/>

那么您可以执行条件语句来查看单击了哪个按钮，如下所示:

if ( isset( $_POST['submit$id'] ) ) { }