python - BeautifulSoup错误消息？

Question

我第一次使用BeautifulSoup。我看了一个youtube视频，模仿了他们的所作所为。我正试图从apt网站上获取租金价格，但我不断收到这样的消息:

Traceback (most recent call last):
  File "C:\Users\Eun Hae Lee\AppData\Local\Programs\Python\Python35-32\rent.py", line 5, in <module>
    sauce = urllib.request.urlopen("http://www.equityapartments.com/washington-dc/georgetown/2400-m-apartments##unit-availability-tile").read()
  File "C:\Users\Eun Hae Lee\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 162, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Users\Eun Hae Lee\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 471, in open
    response = meth(req, response)
  File "C:\Users\Eun Hae Lee\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 581, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Users\Eun Hae Lee\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 509, in error
    return self._call_chain(*args)
  File "C:\Users\Eun Hae Lee\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 443, in _call_chain
    result = func(*args)
  File "C:\Users\Eun Hae Lee\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 589, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

此错误消息的原因是什么？

我使用的代码是

import urllib.request
import bs4 as bs

sauce = urllib.request.urlopen("http://www.equityapartments.com/washington-dc/georgetown/2400-m-apartments##unit-availability-tile").read()
soup = bs.beautifulsoup(sauce, 'html.parser')

print(soup)

感谢您的帮助!

Answer 1

此错误与BeautifulSoup无关-您从远程服务器的urlopen操作中得到400。您需要检查您的URL并确定为什么它不是合法的GET。