python - 第二个def上的语法错误

Question

运行此代码时，我遇到第二个def的麻烦，* de * f乘法():当我收到语法错误时，就会发出def的de问题。

import random
def start () :

    print "Welcome!"
    choose ()

def choose () :

    choice = input """would you like to
     add, subtract, or multiply?
      1       2            3
    """
    if choice = 1 :
        add ()
    if choice = 2 :
        subtract ()
    if choice = 3 :
        multiply ()


def multiply () :

    x = random.random ()
    x = round ()
    y = random.random ()
    y = round ()
    print "What is the answer to: ", x,"*", y, " ?"
    answer = input ": "
    z = x*y
    if answer == z :
        print "you are correct!"
    elif answer < z :
        print "your answer is low! The correct answer was ", z
    elif answer > z :
        print "your answer is high! The correct answer was ", z
    multiply ()

def add () :

    x = random.random ()
    x = round ()
    y = random.random ()
    y = round ()
    print "What is the answer to: ", x,"+", y, " ?"
    answer = input ": "
    z = x+y
    if answer == z :
        print "you are correct!"
    elif answer < z :
        print "your answer is low! The correct answer was ", z
    elif answer > z :
        print "your answer is high! The correct answer was ", z

def subtract () :

    x = random.random ()
    x = round ()
    y = random.random ()
    y = round ()
    print "What is the answer to: ", x,"*", y, " ?"
    answer = input ": "
    z = x*y
    if answer == z :
        print "you are correct!"
    elif answer < z :
        print "your answer is low! The correct answer was ", z
    elif answer > z :
        print "your answer is high! The correct answer was ", z

Answer 1

input是一个函数，因此您必须像调用它一样:

input('Input some stuff: ')

您还可以看到以下几行:

if choice = 1 :

您要编写choice == 1。最后，这部分有点奇怪:

x = random.random ()
x = round ()

您可能想将x传递到round:

x = random.random ()
x = round (x)

或者只是完全跳过该部分并使用randint

x = random.randint(0, 1)