我正在尝试实现PIVOT
,但在其中执行基本操作时遇到问题。
当前表:
week_no username days pick_count duration
------------------------------------------------
Week 50 Beck W Wednesday 227 7978
Week 50 Beck W Friday 320 7481
Week 50 Beck W Friday 282 5718
Week 50 Cockram D Thursday 165 10478
Week 50 Cowell P Thursday 145 14403
Week 50 Cowell P Thursday 159 7450
Week 50 Cowell P Friday 217 13101
...
预期结果:
week_no username monday tuesday wednesday thursday friday saturday sunday
--------------------------------------------------------------------------
Week 50 Beck W NULL NULL 102 NULL 164 NULL NULL
Week 50 Cockram D NULL NULL NULL 56 NULL NULL NULL
Week 50 Cowell P NULL NULL NULL 50 59 NULL NULL
...
预期结果应按如下方式计算:pick_count * 3600/持续时间
。这就是我计算时遇到问题的计算。当像这样PIVOT
时
SELECT
*
FROM
(
SELECT
week_no,
username,
days,
pick_count,
duration
FROM
table
) AS src
PIVOT
(
SUM(pick_count) * 3600 / SUM(duration) FOR days IN (monday, tuesday, wednesday, thursday, friday, saturday, sunday)
) AS pvt
我得到“*”附近的语法不正确
。
最佳答案
PIVOT
不太灵活。
您可以仅使用旧式交叉表方法。
SELECT week_no,
username,
SUM(CASE WHEN days = 'monday' then pick_count end) * 3600
/ SUM(CASE WHEN days = 'monday' then duration end) as monday,
SUM(CASE WHEN days = 'tuesday' then pick_count end) * 3600
/ SUM(CASE WHEN days = 'tuesday' then duration end) as tuesday
/*TODO: Add other five days*/
FROM YourTable
GROUP BY week_no,
username
关于sql-server - 在数据透视表中执行操作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34511019/