php - 如何在以下初学者TwiML代码中调试 “Application Error”语音提示？

Question

我有一个非常基本的应用程序，在该应用程序中，用户受到欢迎，并且可以选择1或2，然后发送给回叫脚本。每当我通过第一个菜单时，它就会给我一个“应用程序遇到错误”消息。

我的脚本如下:

    <?php

    // make an associative array of callers we know, indexed by phone number
    $people = array(
        "+15559990000"=>"A"  );

    // if the caller is known, then greet them by name
    // otherwise, consider them just another caller
    if(!$name = $people[$_REQUEST['From']])
        $name = "caller";

    // now greet the caller
    header("content-type: text/xml");
    echo "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n";
?>
<Response>

    <Gather action="process.php" numDigits="1">
        <Say>Hello <?php echo $name ?>. Welcome to Choons by Yo-say.</Say>
        <Say>To continue as <?php echo $name ?>, press 1.</Say>
        <Say>If you are using a different number but would like to access your account, press 2</Say>
    </Gather>
    <!-- If customer doesn't input anything, prompt and try again. -->
    <Say>Sorry, I didn't get your response.</Say>
</Response>

因此process.php脚本如下所示:

<?php
    header('Content-type: text/xml');
    echo '<?xml version="1.0" encoding="UTF-8"?>';

    echo '<Response>';

    # @start snippet
    $user_pushed = (int) $_REQUEST['Digits'];
    # @end snippet

    if ($user_pushed == 1)
    {
        echo '<Say>You pressed 1</Say>';
    }

    if ($user_pushed == 2) 
    {
        echo '<Say>You pressed 2</Say>';
    }
    else {
        // We'll implement the rest of the functionality in the 
        // following sections.
        echo "<Say>Sorry, I can't do that yet.</Say>";
        echo '<Redirect>mine-or-not.php</Redirect>';
    }

    echo '</Response>';
?>

当我拨入模拟账户时，它将成功通过整个第一个脚本。但是在按下“1”或“2”时，它只是说“对不起，应用程序遇到错误。”谁能发现我的错误？

Answer 1

Twilio的传播者在这里。

有许多调试技巧:

检查App Monitor，以查看Twilio在尝试向您的网站发出请求时捕获的内容。通常，这将为您提供足够的信息以找出正在发生的情况。 App Monitor还允许您“重播”单个Webhook请求，这些请求发送与原始Webhook请求相同的参数，以帮助您诊断故障。

尝试在浏览器中加载PHP文件，或使用Fiddler或Postman之类的工具来模拟Twilio请求的HTTP请求。这将使您可以执行代码，就像Twilio一样向它们发出HTTP请求，但是您可以看到应用程序发送的响应。

希望能有所帮助。