php - PHP脚本中的错误不会传递回CRON

Question

我有一些PHP脚本为我做一些工作，并打印一些日志记录信息。这是调用的结构:

Crontab

*/3 *  *   *   *     sleep 180 && cd /var/www/tasks && ./wrapper.sh start "/usr/bin/php stat-import.php" stat-import >> stat-import.log

包装器

#!/bin/bash

function start
{
    WRAP_CMD="$1"
    WRAP_DESC="$2"
    ARGS=($WRAP_CMD)
    if [[ ( $WRAP_DESC ) && ( -n $WRAP_DESC ) ]]
    then
        OUT_DESC="$WRAP_DESC"
    else
        OUT_DESC="$WRAP_CMD"
    fi
    PID=`ps axw -o pid,command | grep "$WRAP_CMD" | grep -v grep | grep -v "$0" | awk '{print $1}' | awk '{print $1}'`
    if [[ ( $PID ) && ( -n $PID ) ]]
    then
        echo `date +'%Y-%m-%d %H:%M:%S'`" INFO - $OUT_DESC already running"
    else
        echo `date +'%Y-%m-%d %H:%M:%S'`" INFO - $OUT_DESC started"
        $WRAP_CMD
        ECODE=$?
        echo `date +'%Y-%m-%d %H:%M:%S'`" INFO - $OUT_DESC finished"
        exit $ECODE
    fi
}

function stop
{
    [...]
}

function main
{
    if [[ ( $# < 2 ) || ( $# > 3 ) ]]
    then
        echo "Usage: $0 [start|stop] COMMAND [DESCRIPTION]"
        exit 0
    fi
    if [ $1 == "start" ]
    then
        start "$2" "$3"
    elif [ $1 == "stop" ]
    then
        stop "$2" "$3"
    else
        echo "Usage: $0 [start|stop] COMMAND [DESCRIPTION]"
    fi
    exit 0
}

# Script execution:
main "$@"

stat-import.php

<?php
    die("error message");
    // OR
    exit(127);
    // OR
    trigger_error("error_message", E_USER_ERROR);

默认情况下，只有wrapper.sh或我的PHP脚本中的语法错误会导致CRON发送邮件。我的用户定义的stat-import.php错误没有传递给CRON，但进入了日志文件？ ?？

Answer 1

默认情况下，PHP错误会打印到stdout，您的cron会将其重定向到日志文件。您需要将错误打印到stderr，以便将这些错误由cron守护程序邮寄:display_errors setting in PHP docs