javascript - 元素为数组时两个数组之间的区别

Question

var a = [["Green","Medium"],["Green","Small"],["Medium","Red"],["Red","Small"]];

var b = [["Green","Medium"],["Green","Small"],["Medium","Red"]];

So my result will [["Red","Small"]]

并不是说 a.filter(x => !b.includes(x)) 不起作用，因为所有元素都是数组。 我试过类似的东西

    var diff = [];
    a.forEach((res, i) => {
      b.forEach((res2, j) => {
        if (i === j && !_.isEqual(res, res2)) {
          diff.push(res);
        }
      });
    });
console.log(diff);

当不同的元素是最后位置时这不起作用

Answer 1

在lodash中，你可以使用_.differenceWith()和供应_.isEqual()作为执行深度比较的比较器:

const c = _.differenceWith(a, b, _.isEqual);

---

完整片段:

const a = [["Green","Medium"],["Green","Small"],["Medium","Red"],["Red","Small"]];
const b = [["Green","Medium"],["Green","Small"],["Medium","Red"]];

const c = _.differenceWith(a, b, _.isEqual);

console.log(c);

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